Answer:
(-∞, ∞)
Step-by-step explanation:
The domain of a function is the set of all possible input values (x-values).
An asymptote is a line that the curve gets infinitely close to, but never touches.
The arrows on either end of a graphed curve show that the function <u>continues indefinitely</u>. Therefore, we cannot assume there is an asymptote at x = -3 as we cannot see what happens to the curve as x approaches -∞.
Therefore, the domain of the given function is unrestricted:
- Solution: { x | -∞ < x < ∞ }
- Interval notation: (-∞, ∞)
The remaining plant food is: 1 7/12 kg
Step-by-step explanation:
Given
Total Plant food = 3 1/2 kg
Plant food used on Strawberry Plants = 1 2/3 kg
Plant food used on tomato Plants = 1/4 kg
We will first calculate the total food plant used and then subtract the used plant food from the total plant food.
So,
Now,
The remaining plant food is: 1 7/12 kg
Keywords: Division, Fractions
Learn more about fractions at:
#LearnwithBrainly
Answer:
D
Step-by-step explanation:
The basic equation to solve this would be D = RT, which is
D is Distance
R is Rate (speed)
T is time
To find total distance D, we can find individual distances for two legs of the whole.
First Leg:
R = 8
T = a
D = 8a
Second Leg:
R = 7.5
T = b
D = 7.5b
Total distance D is:
D = 8a + 7.5b
Moreover, we know student runs 45 minutes in total hence a + b = 45 or we can say a = 45 - b, so we can replace this in the equation found:
D = 8a + 7.5b
D = 8(45 - b) + 7.5b
Answer choice D is right.
he elements of the Klein <span>44</span>-group sitting inside <span><span>A4</span><span>A4</span></span> are precisely the identity, and all elements of <span><span>A4</span><span>A4</span></span>of the form <span><span>(ij)(kℓ)</span><span>(ij)(kℓ)</span></span> (the product of two disjoint transpositions).
Since conjugation in <span><span>Sn</span><span>Sn</span></span> (and therefore in <span><span>An</span><span>An</span></span>) does not change the cycle structure, it follows that this subgroup is a union of conjugacy classes, and therefore is normal.
