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Rus_ich [418]
2 years ago
13

PLS ANSWER ASAP!!!!! Simplify 5^-4/5^3

Mathematics
1 answer:
Alekssandra [29.7K]2 years ago
5 0

Answer:

None on the above.

Step-by-step explanation:

Here’s what I got:

1/5^-1.

3+(-4)=-1

5^-4/5^3 = 1/5^-1

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S = 40, u<br> 12, mZS = 37
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3 0
3 years ago
Given that ABCD is a parallelogram, what must be proven to prove that the diagonals bisect each other?
Yuliya22 [10]

Answer:

We have to prove  Δ ABO ≅ Δ CDO or,  Δ DAO ≅ Δ BCO.

Step-by-step explanation:

Let us assume that ABCD is a parallelogram having diagonals AC and BD.

We have to prove that in a parallelogram the diagonals bisect each other.

Assume that the diagonals of ABCD i.e. AC and BD intersect at point O.

Therefore, to prove that the diagonals AC and BD bisect each other, we have to first prove that Δ ABO and Δ CDO are congruent or Δ DAO and Δ  BCO are congruent.

In symbol, we have to prove  Δ ABO ≅ Δ CDO or,  Δ DAO ≅ Δ BCO. (Answer)

4 0
3 years ago
Find the lowest common denominator of the following fractions.5/n-2 and n+2/ n^2-4 n - 2 n2 - 4 (n - 2)(n2 - 4)
DanielleElmas [232]

Answer:

(n-2)(n+2)

Step-by-step explanation:

The denominator of the second fraction is the difference of squares, so can be factored using the formula for that.

 (n^2 -4) = (n -2)(n +2)

Now, you will note that the second fraction has a numerator that is equal to one of the factors in the denominator. In other words, the whole fraction can be simplified to ...

 (n +2)/((n +2)(n -2)) = 1/(n -2) . . . . with the restriction n≠-2

This reduced form of the fraction has the same denominator as the first fraction, so you can say that the lowest common denominator is that: (n -2).

If there is some reason you don't want to reduce the second fraction, the lowest common denominator will be (n -2)(n +2).

5 0
4 years ago
One hall can accommodate 65 people. How many halls are required to accommodate 520 people? ​
Mashcka [7]

8 halls would be required to accommodate 520 people in the hall.

As we know that a hall can accommodate 65 people.

To determine the number of hall required for 520 people,

first we need to find that how many halls would be required for one person,

So, we will divide the 1 by 6 to find :

The number of one person accommodate = 1/65 Hall

Then, 520 people required to accommodate = 1/65 × 520

                                                                      = 8 Halls.

[Accommodate: to have enough space for somebody/something, especially for a certain number of people]

To learn more about this Patterned Question visit :

brainly.com/question/17498351

#SPJ9

7 0
1 year ago
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