Answer:
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First lets figure out what -5+5 equals. so -5+5=0. so then -4-0 equals -4. so therefor your answer is -4
Answer:
The angle between the 190 ft. side and the 330 ft. side is ![57.9^o](https://tex.z-dn.net/?f=57.9%5Eo)
Step-by-step explanation:
<u>The Law of Cosines</u>
When we know the value of all sides of a triangle, we can compute all of its interior angles by using the Law of Cosines, which is a generalization of the Pythagoras's theorem. If a,b, and c are the known sides of a triangle and
is the angle formed by sides a and b (opposite to c), then
![\displaystyle c^2=a^2+b^2-2ab\ cos\alpha](https://tex.z-dn.net/?f=%5Cdisplaystyle%20c%5E2%3Da%5E2%2Bb%5E2-2ab%5C%20cos%5Calpha)
We'll use the values a=190, b=330, c=280 because we want to compute the angle opposite to c
![\displaystyle cos\alpha =\frac{a^2+b^2-c^2}{2ab}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20cos%5Calpha%20%3D%5Cfrac%7Ba%5E2%2Bb%5E2-c%5E2%7D%7B2ab%7D)
![\displaystyle cos\alpha =\frac{190^2+330^2-280^2}{2(190)(330)}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20cos%5Calpha%20%3D%5Cfrac%7B190%5E2%2B330%5E2-280%5E2%7D%7B2%28190%29%28330%29%7D)
![\displaystyle cos\alpha =\frac{36100+108900-78400}{125400}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20cos%5Calpha%20%3D%5Cfrac%7B36100%2B108900-78400%7D%7B125400%7D)
![\displaystyle cos\alpha =\frac{66600}{125400}=0,5311](https://tex.z-dn.net/?f=%5Cdisplaystyle%20cos%5Calpha%20%3D%5Cfrac%7B66600%7D%7B125400%7D%3D0%2C5311)
![\displaystyle \alpha= arccos\ 0.5311](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Calpha%3D%20arccos%5C%200.5311)
![\boxed{\displaystyle \alpha= 57.9^o}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cdisplaystyle%20%5Calpha%3D%2057.9%5Eo%7D)
Answer:
13
6
14
Step-by-step explanation:
x+6=7+6=13
p/5=30/5=6
2x+y=2(5)+4=10+4=14