17)
x² + 8 = -8
x² = -8 - 8
x² = 16
x = ±√-16
x = ±√16i
x = <span>±4i
</span>
18)
x² + 5 = -3
x² = -3 - 5
x² = -8
x = ±√-8
x = ±√8i
x = ±2√2i
19)
x² + 3 = 0
x² = -3
x = ±√-3
x = <span>±</span>√3i
hope this helps, God bless!
Hello,
Please, see the detailed solution in the attached files.
Thanks.
There are 3 in. of snow on the ground when it begins to snow 0.5 in./h.
Initial depth of snow = 3 in.
it begins to snow 0.5 in./h. The constant rate of snow is 0.5. So slope = 0.5
Let x be the number of hours
y be the total depth of the snow
To frame linear equation we use y=mx+b
where m is the slope and b is the y intercept (initial depth of snow)
We know m=0.5 and b=3
Replace it in the equation
y = 0.5x + 3
The linear equation that represents the total depth of the snow(y), in inches, after x hours
is y= 0.5x + 3
Answer:
258
Step-by-step explanation:
Set up the two equations needed (x is the adult tickets and y is the student tickets)
x+y=372
6x+2y=1776
Solve by elimination
-2(x+y=372)
=-2x-2y=-744
Cancel like figures:
-2x-2y=-744
6x+2y=1776
= 4x=1032
x=258
Answer:
3
Step-by-step explanation:
This is the graph of y = tan(x) shifted 3 units up.