Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
You mean -2x+5y=20 if it was that's how you do it
so if you're finding the x intercept the y will turn to 0 why because you're only looking for x their's no need for y
so it will be -2x+0=20
-2x=20 if it's multiplication then you change it to division
-2x/-2=20/-2
x=-10
Answer:
4
Step-by-step explanation:
To find the common ratio, take the second term and divide by the first term
24/6 = 4
Check by taking the third term and dividing by the second term
96/24 = 4
The common ratio is 4
Answer: 31.43 cm
Step-by-step explanation:
The length of an arc is calculated using the formula:
X 2
r
where : theta is the angle in degree
r = radius
If the angle is given in Radian , the length can be calculated using the formula:
L = r∅
Since , the angle is given in degree , we will use the first formula.
L =
X 2
r
L =
X 2 X π X 15
L =
X 2 X
X 15
L = 
L = 31.42857143
L ≈ 31.43 cm
Put it on the graph as 2xy=10!