Answer:
h = height reached
-16 t^2 = 1/2 g t^2 where g = 32 ft/sec^2
v t = height due to original vertical speed v
s = initial height
1. -45 = -16 t^2 + 62 t + 0 measuring height from original height
solving quadratic
2. t = 4.5 sec
3. time to reach max height = v / g = 62/32 = 1.94 sec
H (above release point) = -16 (1.94^2) + 62 * 1.94 = 60 ft
4. 2 * 1.94 = 3.88 solved in part 3
5. 1.94 solved on part 3
Check: time to fall 60 + 45 ft = 105 ft
105 = 1/2 g t^2
t = (210 / 32)^1/2 = 2.56 sec
total time = 2.56 * 1.94 = 4.5 sec time to fall + rise time
-45 = -16 * 4.5^2 + 62 * 4.5
-45 = -324 + 279 = -45 checking time to reach -45 feet using given equation
