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2 years ago

Solve the equation 4x^2 – 32x + 64 = 0.

Mathematics

1 answer:

AlexFokin [52]2 years ago

8 0

Answer: x = 4

Step-by-step explanation: 4x^2−32x+64=0

4(x−4)(x−4)=0

x−4=0 x−4=0

x=4

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Consider the following numbers: 7000, 700, 70, 0.7, 0.07, 0.007

masya89 [10]

Answer:

7000= 7 x 10^{3}, 700= 7 x 10^{2}, 70= 7 x 10^{1}, 0.7= 7 x 10^{-1}, 0.07= 7 x 10^{-2}, 0.007= 7 x 10^{-3}

Step-by-step explanation:

YES

6 0

3 years ago

I need help with my homework I’m struggling and don’t understand the equation

Elodia [21]

= -2

y= 2x+6. y= -2x-2
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+2x. +2x
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4x+6= -2
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5 0

2 years ago

Calculate the perimeter and area of this shape.

Bond [772]

area = 25.5 cm²

Step-by-step explanation:

i have shown in the image you have to rotate it to see how i worked the area out

i am very sorry i cant work the perimeter out since i have no idea what the length of the two sides of the triangle are . if you need help on understanding how i worked out the area please let me know .

hopefully i was able to help you in half of the question i am sorry for not helping on the perimeter :)

8 0

2 years ago

If anyone could help answer this question that would be great.

lys-0071 [83]

I believe the answer is 64
First break it off into 2 rectangles on is 4 width and 10 length other is 8 length and 10 width. Then multiple to find area 10•4=40 8•3=24 then add 40+24= 64

3 0

3 years ago

Three numbers are in the ratio 3:9:10. If 10 is added to the last number, then the three numbers form an arithmetic progression.

MrRa [10]

Answer:

 The numbers are 6, 18, and 30 

Step-by-step explanation:

If the three numbers are in the ratio of 3:9:10,

let the numbers be 3x, 9x and 10x.

If 10 is added to the last number to form an arithmetic progression

Then, 3x 9x (10x+10) are the progression

The common difference of an arithmetic progression (d) = T₂ - T₁ = T₃ - T₂

T₂-T₁ = T₃ - T₂ .............. Equation 1

Where T₁ = first term of the progression, T₂ = Second term of the progression, T₃ = third term of the progression

Given: T₁ = 3x, T₂ = 9x, T₃ = 10x +10

Substituting these values into equation 1

9x-3x = (10x+10)-9x

Solving the equation above,

3x = 10+x

3x-x = 10

2x = 10

x = 10/2

x = 2.

Therefore the numbers are 6, 18, and 30 

7 0

3 years ago