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Rudik [331]
3 years ago
15

Solve for a. – 2a+5≤7 eazy 20 points

Mathematics
2 answers:
juin [17]3 years ago
6 0

Answer:

a+5=3.5

or a= -1.5

Step-by-step explanation:

2a+5≤7

now divide 2 into 7

then that 7 would be 3.5 so

a+5=3.5

and a would equal

-1.5

Lena [83]3 years ago
4 0

Answer:

6

Step-by-step explanation:

What minus 5 equals 7? That's right, 12. what times 2 equals 12? 6

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a purse contains ₹550 notes of denomination of ₹10 and ₹50 if the number of rupees 50 notes is one less than of ₹10 notes then f
12345 [234]

Answer:

  9

Step-by-step explanation:

Let x represent the number of ₹50 notes. Then the number of ₹10 notes is (x+1) and the total value of all notes is ...

  ₹50·x + ₹10·(x+1) = ₹550

  ₹60·x = ₹540 . . . . . . . . . . . . subtract ₹10 and collect terms

  x = 9 . . . . . . . . . . . . . . divide by ₹60

The number of ₹50 notes is 9.

7 0
2 years ago
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Find BC if segment AD is an altitude of triangle ABC PLEASE HELP
Vedmedyk [2.9K]

Answer:

BC = 96

Step-by-step explanation:

Since AD is an altitude, then ∠ ADC = 90° , thus

4x + 10 = 90 ( subtract 10 from both sides )

4x = 80 ( divide both sides by 4 )

x = 20

Thus

BC = BD + DC

     = 2x + 3x - 4

    = 5x - 4

    = 5(20) - 4 = 100 - 4 = 96

3 0
3 years ago
Make n the subject of the formula in the equation:t=2π√q/pn​
GarryVolchara [31]

Answer: n = 4π(sq)q/(t(sq)*p)

Step-by-step explanation: please see attachment for clearer details. Thanks!

5 0
3 years ago
find the equation of the perpendicular bisector of segment ab with endpoints a=2,2 and b=-4,6 if the perpendicular bisector inte
aleksklad [387]

Equation of perpendicular bisector is ,  y=\frac{3}{2} x+\frac{11}{2}

Length of both pa and pb are  \sqrt{\frac{65}{4} }  unit.

Slope of segment ab is,   \frac{6-2}{-4-2} =-\frac{2}{3}

So, slope of perpendicular bisector will be, negative of reciprocal of slope of segment ab.

Therefore, slope of perpendicular bisector is,  \frac{3}{2}

Since, perpendicular bisector passes through the mid point of segment ab.

So, coordinate of mid point of segment ab is,

                                             (\frac{2-4}{2},\frac{2+6}{2}  )=(-1,4)

Thus, perpendicular bisector of ab passing through (- 1, 4) and have slope  3/2.

So, equation of angle bisector is,

                                     y=\frac{3}{2} x+\frac{11}{2}

Since, the perpendicular bisector intersects the y-axis at point p

So, coordinate of point p is (0, 11/2)

By applying distance formula,

pa=\sqrt{(2-0)^{2}+(2-11/2)^{2}  }\\\\ =\sqrt{4+\frac{49}{4} }\\\\ =\sqrt{\frac{65}{4} }

pb=\sqrt{(-4-0)^{2}+(6-11/2)^{2}  }\\\\ =\sqrt{16+\frac{1}{4} }\\\\ =\sqrt{\frac{65}{4} }

Learn more,

https://brainly.in/question/31510165

8 0
3 years ago
Simplify 13 over the quantity of negative 3 plus 2i.
QveST [7]

13

−

3

+

2

i

Multiply by

−

3

−

2

i

−

3

−

2

i

to make the denominator of

13

−

3

+

2

i

real.

13

−

3

+

2

i

−

3

−

2

i

−

3

−

2

i

Combine.

13

(

−

3

−

2

i

)

(

−

3

+

2

i

)

(

−

3

−

2

i

)

Expand

(

−

3

+

2

i

)

(

−

3

−

2

i

)

using the FOIL Method.

Tap for more steps...

13

(

−

3

−

2

i

)

−

3

⋅

−

3

−

3

(

−

2

i

)

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⋅

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(

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Simplify.

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13

(

−

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−

2

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)

9

−

4

i

2

Simplify each term.

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13

(

−

3

−

2

i

)

9

+

4

Reduce the expression by cancelling the common factors.

Tap for more steps...

−

3

−

2

i

7 0
3 years ago
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