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Schach [20]
2 years ago
7

If you increase the weight of an object, the frictional force increases but the coefficient does not change why

Physics
1 answer:
aleksandr82 [10.1K]2 years ago
8 0

Answer:

The coefficient of friction should in the majority of cases, remain constant no matter what your normal force is. When you apply a greater normal force, the frictional force increases, and your coefficient of friction stays the same. Here's another way to think about it: because the force of friction is equal to the normal force times the coefficient of friction, we expect (in theory) an increase in friction when the normal force is increased.

One more thing, the coefficient of friction is a property of the materials being "rubbed", and this property usually does not depend on the normal force

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A substance sample has a Mass of 45.0 g, and the Data Safety
marishachu [46]

The volume of the sample is 48.39 cm³.

<h3 /><h3>What is volume?</h3>

The term volume refers to the amount of three-dimensional space taken up by an item or a closed surface

To calculate the volume of the sample, we use the formula below

Formula:

  • D = m/v
  • v = m/D................ Equation 1

Where:

  • m = Mass of the smaple
  • D = Density of the sample
  • v = Volume of the sample.

From the question,

Given:

  • m = 45 g
  • D = 0.93 g/cm³

Substitute these values into equation 1

  • v = 45/0.93
  • v = 48.39 cm³

Hence, the volume of the sample is 48.39 cm³.

Learn more about volume here:brainly.com/question/27710307

#SPJ1

8 0
2 years ago
An object of mass m is dropped from height h above a planet of mass M and radius R.Find an expression for the object's speed as
Mnenie [13.5K]

Answer:

Explanation:

Mass of object = m

Height above planet = h

Mass of planet = M

Radius of planet = R

As we have to find out velocity, so let's apply the law of conservation of energies on initial( when the object was at height) and final( when object hit the surface points.

Initial energy = Final energy

K_{i} + U_{i} = K_{f} + U_{f}

\frac{1}{2}mv_{i} ^{2}  - \frac{GMm}{h+R} = \frac{1}{2}mv_{f} ^{2}  - \frac{GMm}{R}\\v_{i} = 0\\v_{f} ^{2} = 2\frac{GM}{R} - 2 \frac{GM}{h+R}

v_{f} =\sqrt{\frac{2GMh}{R(R+h)} }

4 0
4 years ago
Which has more momentum, a 2.0 kg dog at 41 m/s or a 75 kg pony at 1.0 m/s?
Nesterboy [21]

Answer:

The dog has more momentum than the pony.

Explanation:

To solve this problem, we must remember the formula for calculating momentum, which is given below:

momentum = p = m*v

where m represents the mass of the object and v represents the velocity of the object

Using this knowledge, let's calculate the momentum for the dog and the pony.

Dog: p = m*v = (2kg)*(41 m/s) = 82 kg*m/s

Pony: p = m*v = (75kg)*(1 m/s) = 75 kg*m/s

Since 82 > 75, we can conclude that the dog has more momentum.

Hope this helps!

3 0
4 years ago
It requires 350 joules to raise a certain amount of a substance from 10.0°C to 30.0°C. The specific heat of the substance is 1.2
Akimi4 [234]
I'll assume you are looking for the mass of the object, since that is the missing piece of the puzzle.

The important equation for heat and energy is

Energy = mass × specific heat × change in temperature

Things we know:
Energy needed is 350 J.
Specific heat = 1.2 J/g°C
Temp. change = (30-20)°

Now we just need to plug those in and rearrange the formula to find the mass!

350 = mass × 1.2 × 10
6 0
3 years ago
Read 2 more answers
Which of the following statement is false?
GaryK [48]
I believe the answer would be B.
7 0
3 years ago
Read 2 more answers
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