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2 years ago

If you increase the weight of an object, the frictional force increases but the coefficient does not change why

Physics

1 answer:

aleksandr82 [10.1K]2 years ago

8 0

Answer:

The coefficient of friction should in the majority of cases, remain constant no matter what your normal force is. When you apply a greater normal force, the frictional force increases, and your coefficient of friction stays the same. Here's another way to think about it: because the force of friction is equal to the normal force times the coefficient of friction, we expect (in theory) an increase in friction when the normal force is increased.

One more thing, the coefficient of friction is a property of the materials being "rubbed", and this property usually does not depend on the normal force

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A person is pushing a box.The net external force on the 60-kg box is stated to be 90 N. If the force of friction opposing the mo

Trava [24]

Answer:

a = 1 m/s²

Explanation:

given,

mass of the person = 60 Kg

Net External force exerted = 90 N

force of friction opposing the motion = 30 N

acceleration of the box = ?

Net force = External force applied - frictional force

Net force = 90 - 30

net force = 60 N

we know

F = mass x acceleration

60 = 60 x a

a = 1 m/s²

acceleration of the box is equal to a = 1 m/s²

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3 years ago

A box-shaped metal can has dimensions 5 in. by 19 in. by 4 in. high. All of the air inside the can is removed with a vacuum pump

GuDViN [60]

Answer:

The force is $F = 1397 lb$

Explanation:

From the question we are told that

The length of the box is $l = 19 \ in$

The width of the box is $w = 5 \ in$

The height is $h = 4\ in$

The pressure experience on one of the sides is mathematically represented as

$p = \frac{F}{A}$

Where A is the area of the box which is mathematically evaluated as

$A = l * w$

substituting values

$A = 5 *19$

$A = 95 \ in^2$

This pressure is equivalent to the atmospheric pressure which has a constant value of $p = 14.7 pi$

This implies that

$14.7 = \frac{F}{95}$

=> $F = 14.7 *95$

=> $F = 1397 lb$

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3 years ago

Express 0.00000000062 kg in scientific notation. 6.2 x 1010kg 6.2 x 10-10kg 0.62 x 10-9kg

PilotLPTM [1.2K]

I believe the correct answer from the choices listed above is the second option. The scientific notation of the measurement 0.00000000062 kg would be <span>6.2 x 10^-10 kg. Scientific notation is used to express too large and too small values of numbers. Hope this helps. Have a nice day.</span>

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stealth61 [152]

Answer:

W = 0 J

Explanation:

The amount of work done by gas at constant pressure is given by the following formula:

$W = P\Delta V$

where,

W = Work done by the gas

P = Pressure of the gas

ΔV = Change in the volume of the gas

Since the volume of the gas is constant. Therefore, there is no change in the volume of the gas:

$W = P(0\ m^3)\\$

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Answer:

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