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aleksley [76]
3 years ago
9

A horizontal beam of light of intensity 25 W/m2 is sent through two polarizing sheets. The polarizing direction of the first mak

es a 15° angle with that of the second. Suppose that the initial beam is unpolarized. What then is the intensity of the transmitted light? A. 7.2 W/m2 B. 11.7 W/m2 C. 12.1 W/m2 D. 23.3 W/m E. 24.1 W/m
Physics
1 answer:
Zina [86]3 years ago
7 0

Answer:

option (B)

Explanation:

Intensity of unpolarised light, I = 25 W/m^2

When it passes from first polarisr, the intensity of light becomes

I'=\frac{I_{0}}{2}=\frac{25}{2}=12.5 W/m^{2}

Let the intensity of light as it passes from second polariser is I''.

According to the law of Malus

I'' = I' Cos^{2}\theta

Where, θ be the angle between the axis first polariser and the second polariser.

I'' = 12.5\times Cos^{2}15

I'' = 11.66 W/m^2

I'' = 11.7 W/m^2

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Answer:

4.266 m.

Explanation:

Given,

Speed of the electron = 7.50 x 10⁶ m/s

Magnetic field, B = 1 x 10⁻⁵ T

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Using formula of radius of curvature of the charge particle

r = \dfrac{mv}{qB}

m is mass of electron

q is charge of electron

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3 years ago
The initial speed of a body is 7.1 m/s. What is its speed after 2.23 s if it accelerates uniformly at 2.64 m/s 2 ? Answer in uni
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13.0m/s

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Explanation:

Given parameters:

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Final speed = ?

Solution:

Acceleration is the rate of change of velocity with time.

   a = \frac{V - U}{T}

a  = acceleration

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U = initial speed

T = time taken

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   2.64 = \frac{V - 7.1}{2.23}  

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  V = 5.9 + 7.1 = 13.0m/s

B

Using the same parameters, the speed after a uniform deceleration of -2.64m/s², the negative sign implies deceleration;

 from expression 1;

           V - 7.1  = -5.9

           V = -5.9 + 7.1 = 1.2m/s

learn more:

Acceleration brainly.com/question/3820012

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Explanation:

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Answer:

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Answer:

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