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aleksley [76]
3 years ago
9

A horizontal beam of light of intensity 25 W/m2 is sent through two polarizing sheets. The polarizing direction of the first mak

es a 15° angle with that of the second. Suppose that the initial beam is unpolarized. What then is the intensity of the transmitted light? A. 7.2 W/m2 B. 11.7 W/m2 C. 12.1 W/m2 D. 23.3 W/m E. 24.1 W/m
Physics
1 answer:
Zina [86]3 years ago
7 0

Answer:

option (B)

Explanation:

Intensity of unpolarised light, I = 25 W/m^2

When it passes from first polarisr, the intensity of light becomes

I'=\frac{I_{0}}{2}=\frac{25}{2}=12.5 W/m^{2}

Let the intensity of light as it passes from second polariser is I''.

According to the law of Malus

I'' = I' Cos^{2}\theta

Where, θ be the angle between the axis first polariser and the second polariser.

I'' = 12.5\times Cos^{2}15

I'' = 11.66 W/m^2

I'' = 11.7 W/m^2

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<em><u>M</u></em><em><u>a</u></em><em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u>m</u></em><em><u>a</u></em><em><u>t</u></em><em><u>i</u></em><em><u>c</u></em><em><u>a</u></em><em><u>l</u></em><em><u>l</u></em><em><u>y</u></em><em><u>:</u></em>

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Answer:

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Take east to be +x and north to be +y.

The x component of the velocity is:

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The y component of the velocity is:

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The speed is found with Pythagorean theorem:

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