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Viktor [21]
3 years ago
7

Which reactanat makes cellular respiration more efficient than fermentation when making ATP?

Biology
2 answers:
mixer [17]3 years ago
8 0

The answer is B. Glucose

Ksivusya [100]3 years ago
6 0

Answer: glucose I think?

Explanation: I’m not sure but it should be more efficient.

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Reconstruct the phylogeny that most simply and accurately accounts for the distribution of synapomorphies among ingroup species.
Alina [70]

Complete question:

1). Determine the character states for the following six characters that are present in species OG, 5, 7, 15, 17, 18. Assign the character state found in the outgroup (OG) as a 0 and the alternative derived state a 1; use only two states per character. Example, stem width: 0 = thin, / = thick 1 <em>(Characters and plant species image in the attached files)</em>

2). Score each taxon using the 0 and 1 notation about and add to this matrix <em>(Matrix in the attached files)</em>

4). Reconstruct the phylogeny that most simply and accurately accounts for the distribution of synapomorphies among ingroup species. Given matrices as small and simple as the above example, one can build the tree from the bottom up in a series of sketches, adding clades or branches representing groups with the fewest synapomorphies near the base of the tree and those with the most at the tips. Using the unlabeled phylogeny as a starting point, draw the stepwise construction of a fully resolved phylogeny to account for all of the synapomorphies and include the synapomorphies that identify each clade (the first one, character 2, is included to get you started; this is shared by all members of the ingroup) (<em>Tree in the attached files)</em>

Answer:

  • Characters:
  1. Stem width: Thick-1 // Thin-0
  2. Leaf edge (shape): Pointed-1 // Blunt-0  
  3. Flower base (shape): Narrow-0 // Wide-1
  4. Flower orientation: Downward (Pendant)-1 // Upward (Vertical)-0
  5. Petal color: Purple-1 // Yellow-0
  6. Fruit shape (inset on card, on left): Round-0 // Elongated-1
  • Complete Matrix in the attached files
  • Order in the phylogeny reconstruction: OG --> 7 --> 5 --> 15 --> 17 and 18 (tree + evolutive changes in the attached files)

Explanation:

<em>NOTE: You will find the complete activity in the attached files. </em>

  • The principle of maximum parsimony or maximum simplicity states that among all possible trees within a group of species, the most probable  is the one that requires us to postulate the least number of evolutionary changes. So, to reconstruct a phylogeny we need to choose the tree that requires the less number of changes.
  • To determine the character states for all the six characters, we assigned the number cero to all the characters expressed in the out-group. Thin steam, blunt leaf, narrow flower base, upward flower orientation, yellow petals, and rounded-seeds are all cero states. The other characters are 1.
  • The above information of character state was used to fill in the matrix, specifying which character state belongs to each species according to their traits.
  • The matrix was useful to reconstruct the phylogeny, to identify the autapomorphic trait, and to visualize all the clades.

8 0
3 years ago
Do all changes to dna alter the phenotype of an organism? Explain.
Vesnalui [34]

Answer:

No change occurs in phenotype.

Explanation:

This can happen in many situations:

perhaps the mutation occurs in a stretch of DNA with no function, or perhaps the mutation occurs in a protein-coding region, but ends up not affecting the amino acid sequence of the protein.

3 0
3 years ago
which of the following is NOT a true statement about ATP? A. used ATP is discarded by the cell as waste. B. ATP consists of ribo
nordsb [41]
Its B because all the others are true
6 0
3 years ago
Read 2 more answers
Which activity is most likely a result of a sudden, unexpected hangs in the environment? A. a dog mating to produce offspring B.
cupoosta [38]
It would probably be .D. Plankton populations decreasing.
8 0
3 years ago
Looking at the Punnett square, what are the possible genotypes and frequencies
Rom4ik [11]

Answer:

50% or 1/2 of the children will be heterozygous.

50% or 1/2 of the children will be recessive hom0zygotic.

Explanation:

7 0
3 years ago
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