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Rainbow [258]
3 years ago
7

In the absence of recombination, how many genetically different types of gamete can an organism with six homologous chromosome p

airs produce?
A) 6
B) 12
C) 36
D) 64
E) none of the above
Biology
1 answer:
Black_prince [1.1K]3 years ago
5 0

Answer:

(D) 64

Explanation:

We have given number of chromosome pair that is haploid number = 6

We have to calculate the number of possible gamete in absence of recombination

The number of garnets is given by 2^n where n is haploid number

In question we have given haploid number, that is n=6

So the number of gametes without recombination =2^6=64

So option (d) is the correct answer  

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