The data set is roughly periodic, you can see the data that follows a pattern. For example, data point 1 is (1, 102), the 5 is (5, 98) and 9 is (9, 100).
Every 4 periods, the values resemble each other.
The same can be shown with the point (2, 76) and the point (6, 74) and (10, 75).
Therefore, it can be concluded that the period is 4 and the amplitude approximately 25.
Finally, the correct option is the third.
Period 4 and approximate amplitude of 25
Answer:
a). Yes. Area will be less than 100 square in.
b). Area of octagon = 82 in²
Step-by-step explanation:
From the picture attached,
a). Octagon is inscribed in a square having one side = 10 inches.
Since, octagon is obtained by cutting off the four equal corners of the square,
Area of octagon will be less than the area of the square.
Area of square = (side)²
= 10²
= 100 in²
Therefore, area of octagon will be less than 100 in²
b). Since, corner cut off from the square are equal in shape and area,
Area of one corner (right angle triangle) =
=
= 4.5 in²
Area of 4 corners = 4.5 × 4 = 18 in²
Area of octagon = Area of square - Area of 4 corners removed
= 100 - 18
= 82 in²
Color of the light depends on the temperature.
(Dependent) (Independent)
2²-4²+1+7²
we should solve the numbers with exponents :
4-16+1+49 = -12 + 1 + 49 = -11 + 49 = 38
pls give me brainliest
Answer:
Complementary, 65
106+x=180
Step-by-step explanation:
Complementary angles add to 90, Supplementary angles add to 180
These are complementary angles
x+25 = 90
Subtract 25 from each side
x+25-25 =90-25
x = 65
The next questions they are supplementary angles because they add to 180
106+x=180
Subtract 106 from each side
106-106+x=180-106
x=74