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2 years ago

Which expression is equivalent to (x+3)+y

Mathematics

2 answers:

vodomira [7]2 years ago

6 0

Answer:I hope my explanation helps

Step-by-step explanation:Those are the unknown variables so there would not be a way to solve the problem unless you had numbers you could cross multiply with then once you find out what those are figure out what y is and multiply (x+3)+y the numbers in the (. ) by y then add them

vova2212 [387]2 years ago

6 0

The answer is remove the parentheses. X+3+y

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Find f(2) if f(x) = (x 1)2.

Katyanochek1 [597]

I hope this helps you

x=2

f (2)=(2+1)^2=3^2=9

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3 years ago

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Write the following polynomial in standard form: 4x+3-4x2-10x3

Ne4ueva [31]

Answer:

− 10 x ^3 − 4 x ^2 + 4 x + 3

Step-by-step explanation:

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3 years ago

How many lines of symmetry does the letter G have

Lina20 [59]

Answer:

Step-by-step explanation:

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3 years ago

Nadia is a stockbroker. She earns 13% commission each week. Last week, she sold $4,500 worth of stocks. How much did she make

m_a_m_a [10]

Multiply amount sold by commission rate:

4500 x 0.13 = 585

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2 years ago

The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr

aniked [119]

Answer:

(a) $E(X) = 0.383$

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) $P(x = 4) = 0.000169$

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$E(X) = \frac{n \times r}{N}$

$E(X) = \frac{10 \times 8}{209}$

$E(X) = \frac{80}{209}$

$E(X) = 0.383$

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$P(x = 4) = \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}}$

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$P(x = 4) = \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}}$

$P(x = 4) = \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}}$

$$ P(x = 4) = \frac{70 \times 84944276340}{35216131179263320}$

$P(x = 4) = 0.000169$

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

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2 years ago