2 years ago

Can anyone find the distance?

1 answer:

6 0

Sqrt((y2-y1)^2)+(x2-x1)^2)

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Tatiana [17]

A) 2/3 divided by 5/1
= 2/3 X 1/5
= 2/15 of the book

B) 14X5=70
1/3
2/3
3/3
70+35= 105 pages

4 0

2 years ago

emmasim [6.3K]

Answer:

$x=1$ and $x=4$

Step-by-step explanation:

We have the following system of equations:

$y=\sqrt{x}$ and $y=x-2$

To solve the problem, we need to equal the two equations:

$x-2=\sqrt{x}$ ⇒ $(x-2)^{2} =x$ ⇒ $x^{2} -4x + 4 = x$

⇒ $x^{2} -5x + 4 = 0$

So you need to find two numbers that added equal to 5 and multiplied equal to 4. These two numbers are $x=-1$ and $x=-4$ .

Then, the factorized form of the polynomial is: $(x-1)(x-4)$ .

The, the solution to the system of equations is: $x=1$ and $x=4$ .

5 0

2 years ago

stiv31 [10]

If the rectangle has a fixed width of 300, it means that

$2(l+w)=300 \iff l+w=150 \iff w=150-l$

where $w$ and $l$ are width and length, respetively.

So given the length $l$ , the are would be

$l\times w = l\times (150-l)=-l^2+150l$

7 0

3 years ago

Zepler [3.9K]

Answer:

It is subtracting 4 each time, if it were to go on it would go -16 -20 -24 -28 -32 -36 -40 -44 -48 -52 etc

Step-by-step explanation:

3 0

2 years ago

Svet_ta [14]

X + (x + 10) = 154
2 x + 10 = 154
2 x = 154-10 = 144
x = 72 (ans)
Not sure if it’s right

7 0

3 years ago