Question

If h = -19 and j = 16, what is t{j - h} " alt=" \sqrt{j - h} " align="absmiddle" class="latex-formula">
​

Answer 1

Answer:

$\sqrt{35}$

Step-by-step explanation:

h =-19

j =16

$\sqrt{j-h} = ?$

Substitute values into the given equation

$\sqrt{16-(-19)} \\\\\mathrm{Apply\:rule}\:-\left(-a\right)=a\\\\=\sqrt{16+19}\\\\\mathrm{Add\:the\:numbers:}\:16+19=35\\\\=\sqrt{35}$

Answer 2

Add 16 and 19 in the root.
Answer is root of 35.