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Delvig [45]
3 years ago
15

Solve this its not 48

Mathematics
1 answer:
algol133 years ago
7 0

\begin{cases} 3x+5y=50\\ x+5y=31\\[-0.5em] \hrulefill\\ x+5y=31\\ x = 31-5y \end{cases}\qquad \implies \stackrel{\textit{substituting in the 1st equation}}{3(31-5y)+5y=50} \\\\\\ 93-15y+5y=50\implies 93-10y=50\implies -10y=-43 \\\\\\ y=\cfrac{-43}{10}\implies \boxed{y=\cfrac{43}{10}} \\\\[-0.35em] ~\dotfill\\\\ x = 31-5y\implies x = 31-5\left( \frac{43}{10} \right)\implies x = 31-\cfrac{43}{2}\implies \boxed{x = \cfrac{19}{2}}

\stackrel{~\hfill \textit{\large total for 7x + 5y}}{7\left( \cfrac{19}{2} \right)+5\left( \cfrac{43}{10} \right)\implies \cfrac{133}{2}+\cfrac{43}{2}\implies \cfrac{133+43}{2}\implies \cfrac{176}{2}\implies 88}

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Enter a range of values for x please help me
Brums [2.3K]

Answer:

-5 < x < 9

Step-by-step explanation:

By Hinge theorem,

"If two sides of a triangle are congruent to the two sides of another triangle, and the included angle of one triangle is larger than the included angle of the second, then the 3rd side of triangle one will be larger than the third side of the second"

23 > 21

Therefore, 42° > (3x + 15)°

42° - 15° > 3x

27 > 3x

9 > x

And (3x + 15) > 0

3x > -15

x > -5

Therefore, range for x will be,

-5 < x < 9

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3 years ago
Solve the system of linear equations using elimination. −7x + 3y = −6 −3x + 3y = 6
Marysya12 [62]

Answer:

x = 3 , y = 5

Step-by-step explanation:

Solve the following system:

{3 y - 7 x = -6 | (equation 1)

3 y - 3 x = 6 | (equation 2)

Subtract 3/7 × (equation 1) from equation 2:

{-(7 x) + 3 y = -6 | (equation 1)

0 x+(12 y)/7 = 60/7 | (equation 2)

Multiply equation 2 by 7/12:

{-(7 x) + 3 y = -6 | (equation 1)

0 x+y = 5 | (equation 2)

Subtract 3 × (equation 2) from equation 1:

{-(7 x)+0 y = -21 | (equation 1)

0 x+y = 5 | (equation 2)

Divide equation 1 by -7:

{x+0 y = 3 | (equation 1)

0 x+y = 5 | (equation 2)

Collect results:

Answer:  {x = 3 , y = 5

8 0
3 years ago
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