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Delvig [45]
3 years ago
15

Solve this its not 48

Mathematics
1 answer:
algol133 years ago
7 0

\begin{cases} 3x+5y=50\\ x+5y=31\\[-0.5em] \hrulefill\\ x+5y=31\\ x = 31-5y \end{cases}\qquad \implies \stackrel{\textit{substituting in the 1st equation}}{3(31-5y)+5y=50} \\\\\\ 93-15y+5y=50\implies 93-10y=50\implies -10y=-43 \\\\\\ y=\cfrac{-43}{10}\implies \boxed{y=\cfrac{43}{10}} \\\\[-0.35em] ~\dotfill\\\\ x = 31-5y\implies x = 31-5\left( \frac{43}{10} \right)\implies x = 31-\cfrac{43}{2}\implies \boxed{x = \cfrac{19}{2}}

\stackrel{~\hfill \textit{\large total for 7x + 5y}}{7\left( \cfrac{19}{2} \right)+5\left( \cfrac{43}{10} \right)\implies \cfrac{133}{2}+\cfrac{43}{2}\implies \cfrac{133+43}{2}\implies \cfrac{176}{2}\implies 88}

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A=p (1+r)^t
A future value
P present value 4.98
R rate 0.04
T time

After 3 years
A=4.98×(1+0.04)^(3)
A=5.60

7.50=4.98 (1.04)^t
Solve for t
T=log(7.50÷4.98)÷log(1.04)
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Hope it helps:-)
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A withdrawal of $50 is negative or positive?
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In ΔOPQ, the measure of ∠Q=90°, OQ = 20, PO = 29, and QP = 21. What is the value of the sine of ∠P to the nearest hundredth?
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A) exponential is the right answer.

Step-by-step explanation:

The formula used for increase after same number of time is:

A_t = A_0(1+r)^t\\Here\\A_0\ is\ the\ initial amount\\r\ is\ the\ rate\\and\\t\ is\ time

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A_0 = 35000

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A_t = 35000(1+0.03)^t\\A_t = 35000(1.03)^t

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A) exponential is the right answer.

Keywords: Functions, Exponential function

Learn more about functions at:

  • brainly.com/question/10940255
  • brainly.com/question/10941043

#LearnwithBrainly

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