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3 years ago

Give one factor of the polynomial, factor the polynomial completely. f(x)=x^3-4x^2

Mathematics

1 answer:

Mars2501 [29]3 years ago

6 0

(x^2)(x-4) would he the answer here

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Given that f(x) = 5x − 10 and g(x) = x + 3, solve for f(g(x)) when x = −1. (1 point)?

Viefleur [7K]

F(g(x)) means u solve g(x) first then you plug that value into f(x)
x = -1
g(-1) = -1 + 3 = 2
plug 2 into f(x)
f(2) = 5(2) - 10 = 0

4 0

2 years ago

Does anyone get this I accidentally pressed that by accident

sergiy2304 [10]

Answer:

this has happened to me before. unfortunately I had to refresh the page.

Step-by-step explanation:

write down the answers you already have done.

4 0

2 years ago

The graph of y = x^2 is translated 3 units to the left. The equation for this new graph is:

EastWind [94]

The answer is:
C. Y=(x+3)^2

7 0

2 years ago

Using Rigid motion, explain in detail, why triangle ABC must be congruent to triangle DEF

weeeeeb [17]

Using rigid motion, both of these triangles will be congruent. The reason is because rigid motions include reflections, translations, and rotations.

None of these transformations will affect the size or shape of the figure, therefore keeping them congruent.

7 0

2 years ago

A welder drops a piece of red-hot steel on the floor. The initial temperature of the steel is 2,500 degrees Fahrenheit. The ambi

sergey [27]

Answer: After 18.05 minutes, the temperature of steel becomes 100 degrees.

Step-by-step explanation:

Since we have given that

Initial temperature = 2500

At t = 0,

we get that

$f(t)=Ce^{-kt}+80\\\\2500=C+80\\\\2500-80=C\\\\2420=C$

After 2 minutes, the temperature of the steel is 1500 degrees.

so, it becomes,

$1500=2420e^{-2k}+80\\\\1500-80=2420e^{-2k}\\\\\dfrac{1420}{2420}=e^{-2k}\\\\0.587=e^{-2k}\\\\\ln 0.587=-2k\\\\-0.533=-2k\\\\k=\dfrac{0.533}{2}\\\\k=0.266$

So, We need to find the number of minutes when the temperature of steel would be 100 degrees.

So, it becomes,

$100=2420e^{-0.266t}+80\\\\100-80=2420e^{-0.266t}\\\\20=2420e^{-0.266t}\\\\\dfrac{20}{2420}=e^{-0.266t}\\\\\ln \dfrac{20}{2420}=-0.266t\\\\-4.8=-0.266t\\\\t=\dfrac{4.8}{0.266}\\\\t=18.05$

Hence, after 18.05 minutes, the temperature of steel becomes 100 degrees.

7 0

3 years ago