Give one factor of the polynomial, factor the polynomial completely. f(x)=x^3-4x^2

Hey y’all pls help me , what’s the answer :))

klio [65]

4th one. its simple math bro

7 0

2 years ago

Read 2 more answers

What’s the mean of the data set 17,24,26,13

igor_vitrenko [27]

Answer:

20

Step-by-step explanation:

To find the mean, add up all the numbers in the data set, and then divide by the number of terms in the data set

Add up the numbers in the data set

17+24+26+13

80

<em>Divide </em>

Divide by the number of terms in the data set

In this case, there are 4 terms (17, 24, 26, 13)

80/4=20

The mean of the data set is 20

5 0

3 years ago

Read 2 more answers

In your own words, explain the concept of a variable. Discuss how you can teach a class about the use of variables and how they

vesna_86 [32]

VARIABLE is a symbol which is used for representation in a math.

According to the statement

we have to explain about the what is a variable.

So, VARIABLE is a symbol which is used for representation in a math.

It represent the so many things like Algebra, Matrix,Vector etc. and also so many things.

A variable may also be called a data item.

It is used to represent a data like country name, name, age, date of birth etc.

we know that the every thing is changeable. So, like ther things variables are also changeable.

The changing of variable parameters is called as variation. In problems relating to two or more variables, it is seen that the value of a variable changes with the change in the value.

So, VARIABLE is a symbol which is used for representation in a math.

Learn more about VARIABLE here brainly.com/question/1295072

#SPJ4

8 0

1 year ago

HELP! Find the value of sin 0 if tan 0 = 4; 180 < 0< 270

BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

$\large \boxed{sin \theta = tan \theta cos \theta} \\ \large \boxed{tan^{2} \theta + 1 = {sec}^{2} \theta}$

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

$\large{ {4}^{2} + 1 = {sec}^{2} \theta } \\ \large{16 + 1 = {sec}^{2} \theta } \\ \large{ {sec}^{2} \theta = 17}$

As we know, sec²θ = 1/cos²θ.

$\large \boxed{sec \theta = \frac{1}{cos \theta} } \\ \large \boxed{ {sec}^{2} \theta = \frac{1}{ {cos}^{2} \theta} }$

And thus,

$\large{ {cos}^{2} \theta = \frac{1}{17}} \\ \large{cos \theta = \frac{ \sqrt{1} }{ \sqrt{17} } } \\ \large{cos \theta = \frac{1}{ \sqrt{17} } \longrightarrow \frac{ \sqrt{17} }{17} }$