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Iteru [2.4K]
4 years ago
14

Kal is decorating the outside edge of a square

Mathematics
1 answer:
Grace [21]4 years ago
5 0
Answer: Option A
Take not that this is a square bulletin board thus area = Length Times Base. Notice how it says its a square as well? thus telling us that each side is of equal length

Squaring the value N would give us the value of the one side of the board
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Omg i am bored so answer and get points will mark as brelenzz
Zarrin [17]

Answer:

298

Step-by-step explanation:

random numbers also why did you make this lol

3 0
3 years ago
What is 8,100 in scientific notation?
Rzqust [24]
8.1 I think but there's an app called, tiger something and it tells,you the answers
6 0
3 years ago
What’s the geometric mean of 3 square roots of 5 and 5 square roots of 5
navik [9.2K]

Answer:

5√3

Step-by-step explanation:

The <em>geometric mean</em> (GM) of two numbers x and y is the square root of their product.

Thus, the GM of x and y is √(xy).

The GM of 3√5 and 5√5

= √(3√5 × 5√5)

= √[3 × 5 × (√5)²]

= √(3 × 5 × 5)

= √(3 × 5²)

= 5√3

8 0
4 years ago
Factor the trinomial<br> 10x^2+11X-6
yan [13]

Answer:

Not factorable with rationable numbers

Step-by-step explanation:

You cannot factor this expression with rationable numbers.

6 0
3 years ago
Read 2 more answers
1)Make an area model(Table) or a tree diagram to model all the possible combinations in this situation. 2)What is the theoretica
Ann [662]

Answer:

Example:

A bag contains 3 black balls and 5 white balls. Paul picks a ball at random from the bag and replaces it back in the bag. He mixes the balls in the bag and then picks another ball at random from the bag.

a) Construct a probability tree of the problem.

b) Calculate the probability that Paul picks:

i) two black balls

ii) a black ball in his second draw

Solution:

tree diagram

a) Check that the probabilities in the last column add up to 1.

b) i) To find the probability of getting two black balls, first locate the B branch and then follow the second B branch. Since these are independent events we can multiply the probability of each branch.

ii) There are two outcomes where the second ball can be black.

Either (B, B) or (W, B)

From the probability tree diagram, we get:

P(second ball black)

= P(B, B) or P(W, B)

= P(B, B) + P(W, B)

6 0
3 years ago
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