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3 years ago

Predict what are the real roots of the polynomial equation (x2 - 4)(x + 3)²(X -- 1 = 0.

Mathematics

1 answer:

yaroslaw [1]3 years ago

8 0

The answer is D Sam Makatulong salamander

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Patricia has a 30% discount coupon for a jewelry store. She sees a new ring that she wants to buy. After the 30% discount was ap

prisoha [69]

The answer is $59.15

3 0

4 years ago

PLEASE HELP ASAP! THANK YOU

Dafna1 [17]

Answer:

39 m.

Step-by-step explanation:

The area of a triangle is calculated by the expression given as:

Area = bh/2

where b is the base and h is the height.

We calculate as follows:

270 = b (15) / 2

b = 36

hypotenuse = sqrt ( 15^2 + 36^2 ) = 39

4 0

3 years ago

Please help me !!!!!! I need help

kvv77 [185]

Answer:

y +8 = -4(x -8)

Step-by-step explanation:

You recognize that the given equation is in slope-intercept form:

y = mx + b

with m = 1/4 and b = 5.

A perpendicular line will have a slope that is the negative reciprocal of this value of m, so the desired slope is ...

-1/m = -1/(1/4) = -4

The point-slope form of the equation for a line is ...

y -k = m(x -h) . . . . . for slope m through point (h, k)

Using m=-4 and (h, k) = (8, -8), the point-slope form of the equation for the line you want is ...

y +8 = -4(x -8)

3 0

3 years ago

Please answer quickly I only have 5 mins lol. The ratio of students polled in 6th grade who prefer lemonade to Iced tea is 8:4,

zhannawk [14.2K]

Answer:

Let total students who prefer lemonade is 2a and who prefer ice tea is a.

Students in 6th grade=39

2a+a=39

3a=39

a=39/3

a=13

students who prefer lemonate is 13

and those who prefer ice tea is 2a=26

4 0

3 years ago

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

3 years ago