A vertical asymptote is what you get when you try to divide by 0. To find where you get these, you need to look at the denominator and what values of x will make the denominator equal to 0.
In your denominator, you have (x+7)(x-5)(x-3).
What values of x makes (x+7)(x-5)(x-3)=0?
If x = -7, if x = 5, or if x = 3, then that entire expression will equal zero. (Same idea as when you solve equations by factoring.
Now the only place this can get trickier is if one of those factors — one of (x+7), (x-5), or (x-3) — also appears in the numerator. If that happens, then it’s more involved whether you have an asymptote or not. But that doesn’t happen in this example.
So the short version: Asymptotes happen when you try to divide by zero. Dividing by zero is not a good thing. So you just ask yourself, “What will make the denominator 0?”
40 of the toys weren't dolls. The reason why is 5/8 times 64 is equal to 40.
It’s A because the hundreds place is 5 the tens is 8 which is one less then 9 and the ones is 9 which is more then 8
I think the answer would be the last one. a cylinder with radius 4 units.
Answer:
56 units²
Step-by-step explanation:
Each triangle has an area that is ...
... A = 1/2bh = 1/2·7·4
There are 4 such triangles, so the total area is ...
... 4A = 4(1/2)·7·4 = 2·7·4 = 56 . . . . units²
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An area formula customarily used when the diagonals are pependicular to each other is that the area is half the product of their lengths.
... A = (1/2)d1·d2 = (1/2)·14·8 = 56
