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Amiraneli [1.4K]
4 years ago
11

Find the distance between the two points (-4, -2) and (-4, 3).

Mathematics
2 answers:
melamori03 [73]4 years ago
6 0

Answer:

Using distance formula:

Distance = \sqrt{(-4+4)^2 + (3+2)^2} \\ = \sqrt{25}

= 25 units

Mariulka [41]4 years ago
4 0
It would be 5 because the other person that answered put the square root of 25
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You and a friend are going camping for the night and you both bring camping stoves. Your stove is 25 percent efficient, and uses
lesya692 [45]

<u>Answer-</u> 0.05 lit of propane fuel will your friend need in order to boil 10 cups of water.

<u>Solution- </u>

The more efficient the stove is ,less the fuel you need to burn.

so efficiency and amount of fuel needed are inversely proportional with each other.

Given

Your stove is 25 percent = 0.25 efficient ,will boil 10 cups of water, using 0.1 lit of fuel .

0.25 × 2 = 0.5 =50 percent efficient stove ,will boil 10 cups of water, using 0.1/2 = 0.05 lit of fuel.

(∵ As multipling a factor of 2 with efficiency will make the amount of fuel needed half.)


4 0
3 years ago
Please help with this question
Artemon [7]

Answer:

C.

Step-by-step explanation:

G(x) exceeds f(x) from x = 0 to x = 3.

Then we see that f(x) is 11  at x = 4 and g(x) is 10 at x = 4, so there is an intersection between these 2 points.

After this f(x) far exceeds g(x).

5 0
3 years ago
A _____________ exists between two variables when the values of one variable are somehow associated with the values of the other
zysi [14]

Answer:

Step-by-step explanation:

4 0
3 years ago
Guys please help!!!! i NEED to get these right to pass!!!! I WILL GIVE THE BRAINLIEST!!!!
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6 0
3 years ago
#2 <br> #3 <br> Need help for my discrete math class
miss Akunina [59]

For (2), start with the base case. When n = 2, we have

(n + 1)! = (2 + 1)! = 3! = 6

2ⁿ = 2² = 4

6 > 4, so the case of n = 2 is true.

Now assume the inequality holds for n = k, so that

(k + 1)! > 2ᵏ

Under this hypothesis, we want to show the inequality holds for n = k + 1. By definition of factorial, we have

((k + 1) + 1)! = (k + 2)! = (k + 2) (k + 1)!

Then by our hypothesis,

(k + 2) (k + 1)! > (k + 2) 2ᵏ = k•2ᵏ + 2ᵏ⁺¹

and k•2ᵏ ≥ 2•2² = 8, so

k•2ᵏ + 2ᵏ⁺¹ ≥ 8 + 2ᵏ⁺¹ > 2ᵏ⁺¹

which proves the claim.

Unfortunately, I can't help you with (3). Sorry!

3 0
3 years ago
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