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ollegr [7]
2 years ago
14

Which equation has the same solution(s) as x2 + 6x + 1 = 0?

Mathematics
1 answer:
GarryVolchara [31]2 years ago
3 0
(x+3)2=-9
Got it right on my test
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andreev551 [17]

Answer:

I think acute angle

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If h = 15 units and r = 5 units, what is the volume of the cone
Kaylis [27]
V = (1/3)pi*r^2*h that's the formula to used to get the volume of the cone
5 0
2 years ago
Plz help! Don’t understand this question
solniwko [45]

Answer:

11.91

Step-by-step explanation:

The question says there is a new line that connects V and T. If this line is drawn, the diagram would have a right-angle triangle. This triangle is called TUV.

In triangle TUV, the side length created by the points VT is the hypotenuse.

For right-angle triangles, you can use the Pythagorean theorem to find any side.

It's in the format side² + side² = hypotenuse².

To use the formula, you need to know the length of the other two sides. The length of these sides, because they are exactly horizontal or vertical, is found by subtracting the smaller coordinate from the other (that is not the same).

The lengths of other sides:

VU:

-3 is the same. The length is 3.5 - (-5.75) = 9.25

UT:

-5.75 is the same. The length is 4.5 - (-3) = 7.5

Substitute the lengths into the Pythagorean theorem:

a² + b² = c²

9.25² + 7.5² = c²  Simplify

141.8125 = c²  Find the square root of both sides to isolate c

c = 11.91  Final answer, length of VT

7 0
2 years ago
PLEASE HELP I WILL MARK YOU AS BRAINLEST
denpristay [2]

Answer:

(i) Five number summary: Minimum value = 1, Q_1=18,Median=18.5, Q_3=20.5, Maximum value = 26.

(ii) IQR = 2.5, upper fence = 24.25 and lower fence = 14.25.

(iii) 26 is an outlier of the data.

Step-by-step explanation:

The given data set is

19, 18, 23, 18, 18, 26, 19, 16, 20, 18, 17, 21

Arrange the data set in ascending order.

16, 17, 18, 18, 18, 18, 19, 19, 20, 21, 23, 26

Divide the data set in 4 equal parts.

(16, 17, 18), (18, 18, 18), (19, 19, 20), (21, 23, 26)

Minimum value = 16

Q_1=\frac{18+18}{2}=18

Median=Q_2=\frac{18+19}{2}=18.5

Q_3=\frac{20+21}{2}=20.5

Maximum value = 26

The inter quartile range (IQR) of the data is

IQR=Q_3-Q_1=20.5-18=2.5

Upper fence :

Q_3+1.5(IQR)=20.5+1.5(2.5)=24.25

Lower fence :

Q_1-1.5(IQR)=18-1.5(2.5)=14.25

If the any element of the data set lies out side the upper fence and lower fence, then it is called an outlier.

26 ∉ [14.25, 24.25]

Therefore, 26 is an outlier of the data.

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2 years ago
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Andre45 [30]
I think it can be 605. I'm not sure exactly, but I think it is.
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