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romanna [79]
4 years ago
6

Explain number 2 & 3 please

Mathematics
1 answer:
VLD [36.1K]4 years ago
7 0
1. 3x - 2y = 0 => y = 3/2x
4x + 2y = 14<=> 4x + 2*(3/2x) = 14<=> 7x = 14<=> x = 2 & y = 3
2.3p + q = 7=> q = 7 - 3p
2p - 2q = -6<=> 2p - 2*(7-3p) = -6<=> 2p - 14 + 6p = -6<=> 8p = -6 + 14 = 8<=> p = 1 & q = 4
3.3x - 2y = 1=> x = (1+2y)/3
8x + 3y = 2<=> 8*(1+2y)/3 + 3y = 2<=> 8*(1+2y)/3 - 2 = -3y<=> 3*(8*(1+2y)/3 - 2) = -3*(3y)<=> 8*(1+2y) - 6 = -9y<=> 8 + 16y - 6 = -9y<=> 2 = -25y<=> y = -2/25 & x = 7/25
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Answer:

a) The interval for those who want to go out earlier is between 43.008 and 46.592

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Given that:

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Margin of error (e) = ±4% =

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The mean of the distribution (μ) = np = 128 * 0.35 = 44.8

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b) The probability of those who wanted to start school get out later (p) = 39% = 0.39

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\qquad\qquad\huge\underline{{\sf Answer}}♪

Let's solve ~

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