A random experiment consists of tossing 2 coins and observing heads and tails. What is the correct sample space

Which expressions are equivalent to 8 (negative 10 x + 3.5 y minus 7)? Select two options.

Elza [17]

Question is Incomplete; Complete question is given below.

Which expressions are equivalent to 8 (negative 10 x + 3.5 y minus 7)? Select two options. Negative 80 x + 24.5 y minus 56 Negative 80 x + 28 y minus 56 80 x + 28 y + 56 4 (negative 20 x + 7 y minus 14) Negative 4 (negative 20 x + 7 y minus 14)

Answer:

Negative 80 x + 28 y minus 56

4 (negative 20 x + 7 y minus 14)

Step-by-step explanation:

Given:

$8(-10x+3.5y-7)$

We need to find the equivalent expression for given expression.

Solution:

$8(-10x+3.5y-7)$

First we will apply distributive property for given expression.

$a(x+y) =ax+ay$

So we get;

$8\times-10x+8\times3.5y-8\times7\\\\-80x+28y-56$

Hence first expression equivalent to given expression is $-80x+28y-56$ .

Now again evaluating the expression we get;

We will take 4 as common factor from the expression we get;

$-4\times20x+4\times7y-4\times14\\\\4(-20x+7y-14)$

Hence second expression equivalent to given expression is $4(-20x+7y-14)$ .

3 0

3 years ago

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A pole that is 2.8 mm tall casts a shadow that is 1.37 m long. At the same time, a nearby building casts a shadow that is 36.25

ZanzabumX [31]

Answer:

this is the correct answer

5 0

3 years ago

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On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove

gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time $t_1$ , distance of $d_1$ , v = 40. So

$v = \frac{d}{t}$

$40 = \frac{d_1}{t_1}$

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is $v = 60$ .

On the first day, he drove 2 more hours, which means that for the second day, the time is: $t_1 - 2$

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: $d_1 - 20$

Thus

$v = \frac{d}{t}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

System of equations:

Now, from the two equations, a system of equations can be built. So

$40 = \frac{d_1}{t_1}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

Find the total distance traveled in the two days:

We solve the system of equation for $d_1$ , which gets the distance on the first day. The distance on the second day is $d_2 = d_1 - 20$ , and the total distance is: