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Airida [17]
2 years ago
11

2x - 8 algebraic expression

Mathematics
1 answer:
Angelina_Jolie [31]2 years ago
4 0

Answer:

Because. I need to keep this balanced. I just bring down 2x I didn't do anything with him 8 minus 8 is 0 bring down my equal sign and 20 minus 8 is 12.

Step-by-step explanation:

can you me as brainliest if its right? i need 10000 points and 35 brainliest's to rank up to genius

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Simplify the expression state any excluded values<br> 2a^2-4a+2<br> ---------------<br> 3a^2-3
chubhunter [2.5K]

Answer:

The simplified form is \dfrac{2(x-1)}{3(x+1)}.

x =1 is the excluded value for the given expression.

Step-by-step explanation:

Given:

The expression given is:

\dfrac{2a^2-4a+2}{3a^2-3}

Let us simplify the numerator and denominator separately.

The numerator is given as 2a^2-4a+2

2 is a common factor in all the three terms. So, we factor it out. This gives,

=2(a^2-2a+1)

Now, a^2-2a+1=(a-1)(a-1)

Therefore, the numerator becomes 2(a-1)(a-1)

The denominator is given as: 3a^2-3

Factoring out 3, we get

3(a^2-1)

Now, a^2-1 is of the form a^2-b^2=(a-b)(a+b)

So, a^2-1=(a-1)(a+1)

Therefore, the denominator becomes 3(a-1)(a+1)

Now, the given expression is simplified to:

\frac{2a^2-4a+2}{3a^2-3}=\frac{2(x-1)(x-1)}{3(x-1)(x+1)}

There is (x-1) in the numerator and denominator. We can cancel them only if x\ne1 as for x=1, the given expression is undefined.

Now, cancelling the like terms considering x\ne1, we get:

\dfrac{2a^2-4a+2}{3a^2-3}=\dfrac{2(x-1)}{3(x+1)}

Therefore, the simplified form is \dfrac{2(x-1)}{3(x+1)}

The simplification is true only if  x\ne1. So, x =1 is the excluded value for the given expression.

8 0
3 years ago
Kenidi is shopping for a couch with her dad and hears him ask the salesperson, "How much is your commission?"The salesperson say
denis23 [38]

Answer:37.15

Step-by-step explanation:

6 0
3 years ago
I really need help asap with this math homework,<br> It is due tonight.
boyakko [2]

Answer:1920

Step-by-step explanation:

Sorry if this is not accurate but here is how your gonna do it

Find the constant speed per hour (The quotient is 80) then multiply that by 24 which you will get 1920 Hopefull this helps and its correct :D

7 0
3 years ago
If babe ruth averaged 46 home runs per year, how many home runs did he hit in 12 years
bixtya [17]

Answer:

He hit 552 home runs in 12 years

Step-by-step explanation:

To solve this problem, we will follow the steps below;

Using proportion;

Let x be the number of home runs he hits in 12 years

46 home runs = 1 year

    x                  = 12

cross -multiply

x × 1  = 46× 12

x =  552 home runs

Therefore, he hit 552 home runs in 12 years

3 0
3 years ago
Read 2 more answers
PLEASE HELP ME I REALLY NEED HELP!!!!!
salantis [7]
<h3>Answer:</h3>

A) x > 2; y < 2x

B) compare the locations of B and C to the shaded region of part A

C) plot the solution space on the graph of schools. points D and E are schools Lisa may attend

<h3>Step-by-step explanation:</h3>

<em>Coordinates and Plotting Points</em>

First of all, you must understand how to plot a point on a graph. Each set of coordinates is an ordered pair. "Pair" means there are two of them. "Ordered" means the sequence in which they appear has significance.

The first number in the pair is the x-coordinate, the distance to the <em>right</em> of the point x=0. (A negative value for this coordinate indicates the distance is to the <em>left</em>.)

The second number in the pair is the y-coordinate, the distance <em>up</em> from the point y=0. (A negative value for this coordinate indicates the distance is <em>down</em>.)

The coordinates (1, 3) for point A mean the point is plotted on the graph 1 unit to the right of x=0 and 3 units up from y=0. The other points are plotted in the same way. (See the labeled points on the attachment, and note their relationship to the horizontal (x) and vertical (y) scales.)

<em>Lines and their equations</em>

A line on a graph is the plot of all the (x, y) pairs on the graph that will satisfy a particular equation. Generally, there will be an infinite number of points—too many to list. For example, some of the points that will satisfy the equation

  y = 2x

are (x, y) = any of ... (0, 0), (0.001, 0.002), (903, 1806), (1.23, 2.46). (Note that the second number in the pair (y) is 2 times the first number (x). That's what y=2x means.) When we want to see the relationship between x-values and y-values that satisfy this equation, it is convenient to plot the line on a graph.

We talk about such lines using terms that describe the steepness of the line (its <em>slope</em>) and whether it goes up to the right (positive slope), down to the right (negative slope), or is vertical (undefined slope) or horizontal (zero slope). In Algebra, as in Geometry, knowing only 2 points is sufficient to define the line we're concerned with. One of the points commonly used to describe a line is its "y-intercept", the point where it crosses the vertical line at x=0.

<em>Inequalities</em>

For problems such as this one, it is sometimes convenient to talk about all the points that are above or below (or left or right) of a given line. The symbols >, <, ≥, and ≤ are used in place of the equal sign in the relation describing these points. A relation that uses one of these symbols instead of the equal sign is called an "inequality."

If we write y < 2x, for example, we mean all the points such that the value of y is less than two times the value of x. Above, we said the point (x, y) = (1.23, 2.46) is on the line y=2x. Now, we can add that the point (1.23, 2.00) is part of the solution to y < 2x, since 2.00 is less than 2×1.23.

Half of the x-y coordinate plane will satisfy any such inequality. We show which half that is by using shading—coloring the portion of the plane where the points meet the requirements of the inequality (are part of the solution). In the attached graph, the solution to y < 2x is colored green. The line at the boundary of that region is dashed because points on that line are <em>equal to 2x</em>. They do <em>not</em> satisfy the requirement that the points be less than 2x.

Part A

For separating a pair of points from the rest of the group, it can be useful to consider where the other points fall in relation to a line through those two points. Here, points B and C are both on the vertical line x=3, and all the other points are to the left of that line.

We also notice that nearby points A and F are on a line with slope somewhere between 1 and 3. That is, a line with slope 2 might be used to separate points A, F (and those to their upper left) from points B and C.

These observations give us ideas for inequalities we can write that separate points B and C from the rest of the group. Two of them might be ...

  • x > 2 (shaded blue)
  • y < 2x (shaded green)

While either of these alone would serve to contain only points B and C, the two of them together form a "system" of inequalities whose solution (overlapping regions) contains only points B and C—as required by the problem statement.

Part B

Points B and C can be verified as solutions by noting their position on the graph relative to the solution regions of the given inequalities.

Part C

The graph also shows a plot of the solution to the inequality y > 2x+5. This inequality also has a boundary line with a slope of 2, and it has a y-intercept of 5 (the point where it crosses the vertical line at x=0). The solution region is shaded red.

We can identify the schools Lisa may attend by their labels in the solution region of the inequality on the graph. Those schools are D and E.

6 0
3 years ago
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