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8_murik_8 [283]
2 years ago
7

What is the transformation of the graph from its parent function​

Mathematics
1 answer:
VLD [36.1K]2 years ago
7 0

Answer:

The transformation is left 1 hope it is right

Step-by-step explanation:

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Andreas93 [3]

Answer:

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8 0
3 years ago
The length of a rectangle is (x + 1) cm and its width is 5cm less than its length.
NeX [460]

Answer:

a) the area of a square is in terms of x is

(x+1)^2 centimeter square

b)The length of the rectangle is l = (x+1)

                                       l = 7+1 =8 cm

The width of the rectangle is w = [(x+1)-5]

                                     w = (7+1)-5 =3 cm

Step-by-step explanation:

a) the area of a square is in terms of x is

 area of square is l^{2} = (x+1)(x+1)

                                 = (x+1)^2

b)  Given length is  l = (x+1) cm and

the width is 5 cm less than its length.

so we have take width is w = (x+1)-5 cm

Given area of triangle is  24 cm

Area of rectangle = length X width

24  =  (x+1)(x+1 -5 )

now simplification 24 = (x+1)^2 - 5 (x+1)

apply (a+b)^2 = a^2+2 a b+b^2

x^2+2 x+1-5 x-5 =24

x^2 -3 x -4-24=0

x^{2} -3 x -28 =0

now find factors of 28  = 7 X 4 is  

x^{2} -7 x+4 x-28=0

x(x-7)+4(x-7)=0

(x+4)(x-7)=0

x = -4 and x=7

there fore you have to choose x = 7

The length of the rectangle is l = (x+1)

                                       l = 7+1 =8

The width of the rectangle is w = [(x+1)-5]

                                     w = (7+1)-5 = 3

<u>Verification:-</u>

Given area of rectangle  = 24 = 8 X 3

                                           24 =24

so we can not choose x=-4

we have to choose x =7 only

7 0
3 years ago
Factor 5x^2+26x+24 ?
SashulF [63]
First u add all of them and then multiple 2 numbers then theres ur answer
4 0
2 years ago
A “stick” object of height 10 cm is standing in front of a point X–ray source at a distance of 50 cm from the source. The detect
blagie [28]

Answer:

40 cm.

Step-by-step explanation:

Given,

height of the object = 10 cm

Distance of the object from the X-ray= 50 cm

Distance of detector from the source = 2 m = 200 cm

Height of the image, h = ?

Now,

\tan \theta = \frac{P}{B}

\tan \theta = \frac{10}{50}

\tan \theta = \frac{1}{5}

Again applying

\tan \theta = \frac{P}{B}

\frac{1}{5} = \frac{h}{200}

h = 40 cm

Hence, height of the image is equal to 40 cm.

6 0
2 years ago
What is the area, height, and base of this triangle?
Minchanka [31]
This should be your answer

7 0
2 years ago
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