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Nady [450]
3 years ago
15

when ramona went out with her 3 sisters,they spent $58 plus tax on there meal . they also left a 15% tip.if they divided up the

bill evenly ,how much did each of them spend?
Mathematics
1 answer:
Akimi4 [234]3 years ago
3 0

Problem:

Ramona went out with her 3 sisters, they spent $58 plus 9% tax on their meal. They also left 15% tip. If they divided up the bill evenly, how much did each of them spend?

Solution:

the solution is in the pic

Answer:

Each of them did spend $23.97

I did this before i got a 100%

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Distance between points (−4, 3) and (−2, −1)?
sammy [17]

\sqrt{ {( - 4 + 2)}^{2} +  {(3 + 1)}^{2}  }  =  \\  \sqrt{4 + 16}  =  \sqrt{20}
5 0
3 years ago
99 Points for correct answer!!!!!!!!!
3241004551 [841]

The equation given is:

15x - 3y = 21


Slope intercept form is:

y = mx + b


15x - 3y = 21

-15x -15x

-------------------

-3y = -15x + 21

/-3 /-3 /-3

---------------------

y = 5x -7


The answer is: y = 5x - 7


Hope I helped!


-Char

3 0
3 years ago
Consider the sequence: 3, 8, 13, 18, 23, ...The recursive formula for this sequence is:an = an-1 + 5In a COMPLETE sentence, expl
Akimi4 [234]

Answer:

a_8=38

Step-by-step explanation:

<u>Recursive sequence </u>

In a recursive sequence formula, each term a_n is computed as a function of one or more previous terms. In the formula

a_n=a_{n-1}+5

n is the number of the term we want to calculate. If n=8, then the formula becomes

a_8=a_{7}+5

We can see a_{n-1} is the previous term. It means we need a_7 to be able to compute a_8. But we also need a_6 to compute a_7 and so on until some known data is reached. The question provides five terms, a_5=23.

a_6=a_5+5=28

a_7=a_6+5=33

a_8=a_7+5=38

a_8=38

4 0
3 years ago
Please help -(2w+4.2x+3.4)
velikii [3]

Answer:

-2w - 4.2 - 3.4

Step-by-step explanation:

I use the calculator

3 0
3 years ago
Given that α and β are the roots of the quadratic equation <img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B6x-7%3Dp" id="Tex
siniylev [52]

Answer:

\large \boxed{\sf \ \ \ p=-11 \ \ \ }

Step-by-step explanation:

Hello,

\alpha \text{ and } \beta \text{ are the roots of the following equation}

   2x^2+6x-7=p

It means that

   2\alpha^2+6\alpha-7=p \\\\2\beta ^2+6\beta -7=p \\\\

And we know that

\alpha= 2\cdot \beta

So we got two equations

   2(2\beta)^2+6\cdot 2 \cdot \beta -7=p \\\\8\beta^2+12\beta -7=p\\\\ and \ 2\beta ^2+6\beta -7=p \ So \\\\\\8\beta^2+12\beta -7 = 2\beta ^2+6\beta -7\\\\6\beta^2+6\beta =0\\\\\beta(\beta+1)=0\\\\ \beta =0 \ or \ \beta=-1

For \beta =0, \ \ \alpha =0, \ \ p = -7

For \beta =-1, \ \ \alpha =-2, \ \ p= 2-6-7=-11, \ p=2*4-12-7=-11

I assume that we are after two different roots so the solution for p is p=-11

b) \alpha +2 =-2+2=0 \ and \ \beta+2=-1+2=1

So a quadratic equation with the expected roots  is

x(x-1)=x^2-x

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

3 0
3 years ago
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