Answer:
The minimum score required for admission is 21.9.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
A university plans to admit students whose scores are in the top 40%. What is the minimum score required for admission?
Top 40%, so at least 100-40 = 60th percentile. The 60th percentile is the value of X when Z has a pvalue of 0.6. So it is X when Z = 0.255. So
The minimum score required for admission is 21.9.
To find the common ratio, u take ur 2nd term, and divide it by ur 1st term
(-1/6) / (5/12) =
-1/6 * 12/5 =
- 2/5 <== ur common ratio
First, we can write the equation of the line using the information provided:
Now, we can create a table:
Finally, we can graph the line:
Okie doke. So, we are rounding this number to the nearest thousandths place, which is three digits behind the decimal. The rules for rounding are if the number is 5 or more in the digit behind it, the number goes up. If it is 4 or less, the number goes back. In other words, we depend on the digit right of the digit we are rounding to in order to see what we do. The number we are rounding is 1.49882. The 8 is in the thousandths place and the 8 is to the right of that, which is the ten thousandths place. Because 8 is greater than 5, the number rounds up. So the number rounded to the nearest thousandth is 1.500.
Answer:
1. D. 1
2. B. y=a³/x
3. A. y=1/x
Step-by-step explanation:
too long to give te explanations but they're there in the attachments
