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MrRa [10]
3 years ago
13

• R7.9 Write enhanced for loops for the following tasks.

Computers and Technology
1 answer:
alexdok [17]3 years ago
3 0

Answer:

a is the correct answer

Explanation:

correct me if I'm wrong hope it's help thanks

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The ___________ method returns the length of an array.
MaRussiya [10]

Answer:

A. Append

Explanation:

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3 years ago
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Assume that you have an array of integers named arr. Which of these code segments print the same results?
tresset_1 [31]

Answer:

II and III only

Explanation:

In Code segment II, the output of the array will be started form arr[0] and ends at the arr[length]. Because loop starts from 0 and ends at length of array. This will print the full array data.

In code segment III, the output will be all values of array as loop starts form first index and ends at last index.

On the other hand I code segment prints all array values except last value of the array. As the loop shows that, it will terminate at second last value of the array.

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3 years ago
Putting the word int into a code will create a string variable?
loris [4]

Answer:

Yes it will create a string variable

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Which tools are found in the Quick Analysis feature? Check all that apply.
a_sh-v [17]

Answer:

A, C, E

Explanation:

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3 years ago
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Integral 3t+ 1 / (t + 1)^2​
Verizon [17]

Answer:

3ln|t+1|+\frac{2}{t+1} +C

Explanation:

We'll be using u-substitution for this problem.

Let

u=t+1\\du=dt

Substitute

\int\limits {\frac{3u-2}{u^2}} \, du

Split the fraction

\int\limits {\frac{3u}{u^2} } \, du -\int\limits {\frac{2}{u^2} } \, du

Move the constants out

3\int\limits {\frac{u}{u^2}du -2\int\limits {u^{-2}} \, du

Simplify

3\int\limits {\frac{1}{u}du -2\int\limits {u^{-2}} \, du

Integrate

3ln|u|+\frac{2}{u} +C

Substitute

3ln|t+1|+\frac{2}{t+1} +C

5 0
3 years ago
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