Answer:
public class Digits
{
public static boolean allDigitsOdd(int num)
{
boolean flag=true;
int rem;
while(num>0)
{
rem=num%10;
num=num/10;
if(rem%2==0) // if a even digit found immediately breaks out of loop
{
flag=false;
break;
}
}
return flag; //returns result
}
public static void main(String args[])
{
System.out.println(allDigitsOdd(1375)); //returns true as all are odd digits
}
}
OUTPUT :
true
Explanation:
Above program has 2 static methods inside a class Digits. Logic behind above function is that a number is divided by 10 until it is less than 0. Each time its remainder by 0 is checked if even immediately breaks out of the loop.
Answer:
The answer is "Option A".
Explanation:
In the given code an integer array "x" is defined, that stores some elements and another integer variable "a" is declared, that holds a value that is "10". In this code a conditional statement is defined, which checks array element value, in if block element of array that position is 2 is greater then the element of array that position is 5.if this condition is true, so variable a value is change that is equal to 5. In else block if the above condition is not true so the value of a variable is equal to 8, and another options is wrong that can be described as follows:
- In option B, The given condition is not false, that's why it is not correct.
- In option C, The value of variable a is changed when condition is true or false, that's why it is not correct.
- In option D, It is wrong because we can compare array elements.
Explanation:
Answer in the attached image...
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