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2 years ago

11

How to solve 22 – 3y > 7

1 answer:

nikklg [1K]2 years ago

3 0

Answer:

y < 5

Step-by-step explanation:

22 – 3y > 7

=> 22 – 7 > 3y

=> 15 > 3y

=> y < 5

Therefore, y < 5 is the solution.

Hoped this helped.

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If P is the orthocenter of △ABC, AB = 13, BF = 9,and FC = 5.6, find each measure & the perimeter of triangle ABC.

harina [27]

Answer:

$Perimeter = 38.6$

Step-by-step explanation:

Given

$A\ B = 13$

$B\ F = 9$

$F\ C = 5.6$

Required

Calculate the perimeter of A B C

To calculate the perimeter of A B C, we sum up the sides of the triangle

i.e.

$Perimeter = A B + B\ C + A\ C$

AB is given in the question already.

So, we need to calculate B F and F C

To solve for BF, we consider triangle B F C

Using Pythagoras Theorem, we have:

$B\ C^2 = B\ F^2 + F\ C^2$

Substitute values for BF and FC;

$B\ C^2 = 9^2 + 5.6^2$

$B\ C^2 = 81 + 31.36$

$B\ C^2 = 112.36$

$B\ C^2= \sqrt{112.36$

$B\ C = 10.6$

Next, we calculate A C.

To calculate A C, we need to calculate A F, considering triangle B F A

Using Pythagoras Theorem, we have:

$A\ B^2 = B\ F^2 + A\ F^2$

Substitute values for B F and A B;

$13^2 = 9^2 + A\ F^2$

$169= 81 + A\ F^2$

$A\ F^2 = 169 - 81$

$A\ F^2 = 88$

$A\ F = \sqrt{88$

$A\ F = 9.4$

Since F lies on line A C:

$A\ C = A\ F + F\ C$

$A\ C = 9.4 + 5.6$

$A\ C = 15.0$

Recall that:

$Perimeter = A\ B + B\ C + A\ C$

$Perimeter = 13 + 10.6 + 15.0$

$Perimeter = 38.6$

<em>Hence, the perimeter is 38.6</em>

3 0

2 years ago

The maxwell family goes out for dinner and the price of the meal is $60 the sales tax on the meal is 7% and they also want to le

sukhopar [10]

So we start with the $60 untouched.

Then we add the tax which is $60•0.07= 4.20 that is the tax

Then add the tax to the total $60 + $4.20= $64.20

Next we must add the tip so $60•0.15= 9.

Then $64.20 + $9.00 = $73.20

Total cost of meal $73.20

Any questions? :)

4 0

2 years ago

Read 2 more answers

Find the volume of the solid.<br> 11 cm<br> 11 cm<br> 11 cm

grin007 [14]

Answer:1331cm

Step-by-step explanation:vol=lbh

11*11*11cm=1331cm

6 0

3 years ago

(3 x 10e-4) ( 3 x 10e7)

Rina8888 [55]

The answer is 9000..

5 0

2 years ago

The energy released by metabolism of 1 average candy bar is 1 x 10^6 joules.

Elis [28]

Answer: 32

Step-by-step explanation:

Given: The energy needed for 1 hour of running for an adult $=4.5\times10^6\ joules.$

Therefore. the energy needed for seven hours of running= $=7\times4.5\times10^6\ joules.=31.5\times10^6\ joules$

Since, he energy released by metabolism of 1 average candy bar $=1\times10^6\ joules.$

Therefore, the number of candy bars an adult need to eat to supply the energy needed for seven hours of running.= $\frac{31.5\times10^6}{1\times10^6}=31.5\approx32$

Hence, the adult need to eat 32 candies to supply the energy needed for seven hours of running.

3 0

2 years ago