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julia-pushkina [17]
3 years ago
15

PLEASE HELP I AM ON A TIME LIMIT

Mathematics
1 answer:
Alinara [238K]3 years ago
5 0

Answer:

  (a) even: J, K, M, O; odd: L, N

  (b) L and O are connected to J

  (c) N is of degree 3

Step-by-step explanation:

Count the edge ends that intersect each vertex. You get ...

  J-2, K-2, L-3, M-2, N-3, O-4

These numbers are the <em>degree</em> of the vertex.

a) Vertices with even degree are J, K, M, O, since these have degrees of 2, 2, 2, and 4, respectively--all even numbers.

Vertices with odd degree are L and N, since these both have degree 3, an odd number.

__

b) The vertices that are adjacent to J are the ones at the other ends of the edges that intersect vertex J. One of those two edges connects to vertex L; the other to vertex O. J is adjacent to L and O.

__

c) When we counted edges in part (a), we found vertex N to be of degree 3.

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Answer:

Evaluate the terms inside of the parentheses

Step-by-step explanation:

According to PEMDAS, you always start solving an equation by answering what is inside of the parentheses first. (That's what the 'P' in PEMDAS stands for!)

Therefore, this is the correct answer.

8 0
4 years ago
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How to tell if speed is increasing or decreasing calculus?
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Otherwise, you only need the initial and finak value to find the difference.

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4 years ago
Identify all the real solutions of the graph below
Marizza181 [45]
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3 years ago
Are these linear functions or nonlinear functions, please help ive only gotten fake answers and im on a timed test i just need h
Diano4ka-milaya [45]

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y = -4 + 2x is linear.

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7 0
2 years ago
Verify that the function satisfies the three hypotheses of Rolle's Theorem on the given interval. Then find all numbers c that s
valkas [14]
<h2>Answer with explanation:</h2>

Rolle's Theorem states that:

If f is a continuous function in [a,b] and is differentiable in (a,b)

such that f(a)=f(b)

Then there exist a constant c in between a and b i.e. c∈[a,b]

such that:  f'(c)=0

Here we have the function f(x) as:

f(x)=4x^2-8x+3 where x∈[-1,3]

  • Since the function f(x) is a polynomial function hence it is continuous as well as differentiable over the interval [-1,3].

Also,

f(-1)=15

(Since,

f(-1)=4\times (-1)^2-8\times (-1)+3\\\\f(-1)=4+8+3\\\\f(-1)=15   )

and f(3)=15

( Since,

f(3)=4\times 3^2-8\times 3+3\\\\f(3)=36-24+3\\\\i.e.\\\\f(3)=15 )

  • i.e. f(-1)=f(3)

Hence, there will exist a c∈[-1,3] such that f'(c)=0

f'(x)=8x-8\\\\i.e.\\\\f'(x)=0\\\\imply\\\\8x-8=0\\\\i.e.\\\\x-1=0\\\\i.e.\\\\x=1

Hence, the c that satisfy the conclusion is: c=1

7 0
3 years ago
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