Question

Suppose the ages of multiple birth (3 or more babies) are normally distributed with a mean age of 31.7 years and a standard deviation of 5.2 years. What percent of these mothers are between the ages 30-35

Answer 1

Answer:

The percent of these mothers are between the ages 30-35 is 36.53%

Step-by-step explanation:

we are given

mean of age =31.7 years

$\mu=31.7$

standard deviation of 5.2 years

$\sigma=5.2$

For age=30 years:

x=30

we can find z-score

$z=\frac{x-\mu}{\sigma}$

we can plug values

$z=\frac{30-31.7}{5.2}$

$z=-0.32692$

For age=35 years:

x=35

we can find z-score

$z=\frac{x-\mu}{\sigma}$

we can plug values

$z=\frac{35-31.7}{5.2}$

$z=0.63462$

now, we can use normal distribution table

$P(-0.32692$

now, we can find percentage

$=0.3653\times 100$

=36.53%