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Tju [1.3M]
3 years ago
10

Suppose the ages of multiple birth (3 or more babies) are normally distributed with a mean age of 31.7 years and a standard devi

ation of 5.2 years. What percent of these mothers are between the ages 30-35
Mathematics
1 answer:
artcher [175]3 years ago
4 0

Answer:

The percent of these mothers are between the ages 30-35 is 36.53%

Step-by-step explanation:

we are given

mean of age =31.7 years

\mu=31.7

standard deviation of 5.2 years

\sigma=5.2

For age=30 years:

x=30

we can find z-score

z=\frac{x-\mu}{\sigma}

we can plug values

z=\frac{30-31.7}{5.2}

z=-0.32692

For age=35 years:

x=35

we can find z-score

z=\frac{x-\mu}{\sigma}

we can plug values

z=\frac{35-31.7}{5.2}

z=0.63462

now, we can use normal distribution table

P(-0.32692

now, we can find percentage

=0.3653\times 100

=36.53%


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