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Inessa [10]
3 years ago
15

How do you subtract (2/3)-(1/6)

Mathematics
1 answer:
kakasveta [241]3 years ago
8 0
What is 2/3 - 1/6?<span><span>Here's how to subtract 1/6 from 2/3:<span><span>23</span>−<span>16</span></span></span><span>Step 1We can't subtract two fractions with different denominators. So you need to get a common denominator. To do this, you'll multiply the denominators times each other... but the numerators have to change, too. They get multiplied by the other term's denominator.So we multiply 2 by 6, and get 12.Then we multiply 1 by 3, and get 3.Next we give both terms new denominators -- 3 × 6 = 18.So now our fractions look like this:<span><span>1218</span>−<span>318</span></span></span><span>Step 2Since our denominators match, we can subtract the numerators.12 − 3 = 9So the answer is:<span>918</span></span><span>Step 3Last of all, we need to simplify the fraction, if possible. Can it be reduced to a simpler fraction?To find out, we try dividing it by 2...Nope! So now we try the next greatest prime number, 3...Are both the numerator and the denominator evenly divisible by 3? Yes! So we reduce it:<span><span>918</span>÷ 3 =<span>36</span></span>Let's try dividing by 3 again...Are both the numerator and the denominator evenly divisible by 3? Yes! So we reduce it:<span><span>36</span>÷ 3 =<span>12</span></span>Let's try dividing by 3 again...No good. 3 is larger than 1. So we're done reducing.There you have it! The final answer is:<span><span>23</span>−<span>16</span>=<span><span>12</span></span></span></span></span>There are 3 simple steps to subtract fractions<span>Make sure the bottom numbers (the denominators) are the same.Subtract the top numbers (the numerators). Put the answer over the same denominator.<span>Simplify the fraction (if needed).



</span></span>
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What is the quotient (3x^2+8x-3)/ (x+3)
Dvinal [7]

Answer:

The quotient ix 3x - 1.

Explanation:

Use Long division:

        3x - 1     <------------quotient.

        ---------------------

x + 3) 3x^2 + 8x + 3

         3x^2 + 9x

          -------------

                      -x + 3

                      -x - 3

                        ------

                             6 <---------remainder.

6 0
2 years ago
Find the real zeros of f(x); there are 4 zeros
ziro4ka [17]

Answer:

x = 4 or x = 1 or x = -2 or x = -3/2

Step-by-step explanation:

Solve for x over the real numbers:

2 x^4 - 3 x^3 - 21 x^2 - 2 x + 24 = 0

The left hand side factors into a product with four terms:

(x - 4) (x - 1) (x + 2) (2 x + 3) = 0

Split into four equations:

x - 4 = 0 or x - 1 = 0 or x + 2 = 0 or 2 x + 3 = 0

Add 4 to both sides:

x = 4 or x - 1 = 0 or x + 2 = 0 or 2 x + 3 = 0

Add 1 to both sides:

x = 4 or x = 1 or x + 2 = 0 or 2 x + 3 = 0

Subtract 2 from both sides:

x = 4 or x = 1 or x = -2 or 2 x + 3 = 0

Subtract 3 from both sides:

x = 4 or x = 1 or x = -2 or 2 x = -3

Divide both sides by 2:

Answer:  x = 4 or x = 1 or x = -2 or x = -3/2

7 0
3 years ago
Read 2 more answers
I need help with this problem
Arada [10]

Answer:

65.56°

Step-by-step explanation:

We know that if we take dot product of two vectors then it is equal to the product of magnitudes of the vectors and cosine of the angle between them

That is let p and q be any two vectors and A be the angle between them

So, p·q=|p|*|q|*cosA

⇒cosA=\frac{u.v}{|u||v|}

Given u=-8i-3j and v=-8i+8j

|u|=\sqrt{(-8)^{2}+ (-3)^{2}} =8.544

|v|=\sqrt{(-8)^{2}+ (8)^{2}} =11.3137

let A be angle before u and v

therefore, cosA=\frac{u.v}{|u||v|}=\frac{(-8)*(-8)+(-3)*(8)}{8.544*11.3137} =\frac{40}{96.664}

⇒A=arccos(\frac{40}{96.664} )=arccos(0.4138 )=65.56

Therefore angle between u and v is 65.56°

5 0
2 years ago
Plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz
Andrei [34K]

Answer:

Circle 1=6x+2y

Rectangle 4 = 3x+y

Circle 4 = 5x

Step-by-step explanation:

4x+3y and 2x-y can be added to find result for the circle.

Let C1 represent circle 1

4x+3y+2x-y=C1\\

Combining\:like\:terms\\

4x+2x+3y-y=C1

6x+2y=C1

So, The result is: C1=6x+2y

Now, We need to solve:

Let R1 represent rectangle 4

x+4y + R1 = 4x+5y

R1=4x+5y-(x+4y)

R1=4x+5y-x-4y

R1=4x-x+5y-4y

R1=3x+y

So, Solving x+4y + R1 = 4x+5y, We get R1 = 3x+y

Now, We need to solve the equation:

Let C4= Circle 4

2x-y+3x+y=C4

Combining the like terms

2x+3x-y+y=C4

5x=C4

So, Solving 2x-y+3x+y=C4 we get C4 = 5x

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its the one with 2000$ in it

Step-by-step explanation:

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