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2 years ago

8

Mandy is setting up for a reception. For the number of seats needed, she knows she can use either 8 seats at each table with non

e left over, or 10 seats at each table with none left over. Which is the least number of seats she is setting up?

1 answer:

kenny6666 [7]2 years ago

8 0

100 according to my teacher

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This question is confusing. Please help me!This question is confusing. Please help me!

Lera25 [3.4K]

Answer:

(C) 1/2

Step-by-step explanation:

s + 3s = 4s
t + 3t = 4t

If 4s is 2 more than 4t, then:

4s = 2+ 4t
4s - 4t = 2
4s/4 - 4t/4 = 2/4
s - t = 1/2

(C) is the answer

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Matching inequalities with statements

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closed, or shaded, circle is used to represent the inequalities greater than or equal to (≥) or less than or equal to (≤) . The point is part of the solution. An open circle is used for greater than (>) or less than (<). The point is not part of the solution.

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Write 85% as it's fraction, as simply as possible

cricket20 [7]

Hey ! there

Answer:

Simplest fraction form of 85% is <u>1</u><u>7</u><u>/</u><u>2</u><u>0</u><u> </u><u>.</u>

Step-by-step explanation:

Question says that we have to write the <u>simplest</u><u> </u><u>form </u><u>of </u><u>8</u><u>5</u><u>%</u><u> </u><u>as </u><u>it's </u><u>fraction</u><u> </u><u>.</u>

<u>Solution </u><u>:</u><u> </u><u>-</u>

$\quad \longrightarrow \qquad \:85\%$

We know that ,

Percent ( % ) = <u>1</u><u>/</u><u>100</u>

So ,

$\quad \longrightarrow \qquad \: 85 \times \dfrac{1}{100} \:$

or ,

$\quad \longrightarrow \qquad \: \dfrac{85}{100}$

Reducing the fraction by cancelling it by 5 :

$\quad \longrightarrow \qquad \: \dfrac{ \cancel{85}}{ \cancel{100}}$

We get :

$\quad \longrightarrow \qquad \: \pink{\underline{\boxed{\frak{\dfrac{17}{20} }}}} \quad \bigstar$

Now , we can't reduce 17/20 .

<u>Henceforth</u><u> </u><u>,</u><u> </u><u>1</u><u>7</u><u>/</u><u>2</u><u>0</u><u> </u><u>is </u><u>the </u><u>simplest</u><u> </u><u>form </u><u>of </u><u>8</u><u>5</u><u>%</u><u> </u><u>.</u>

<h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>

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