Explanation:
Molar mass of
is 94 g/mol. As it is known that number of moles is equal to mass of a substance divided by its molar mass.
Then, calculate the number of moles as follows.
No. of moles =
in 1 s
= 0.914 mol
So, in 60 sec number of moles will be equal to 0.914 x 60 = 54.89 mol/min.
Hence, the molar flow rate = 54.89 mol/min
Also, density is equal to mass of a substance divided by its volume.
Density = ![\frac{mass}{volume}](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7Bvolume%7D)
Volume = ![\frac{mass}{Density}](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7BDensity%7D)
= ![\frac{86.0 g}{1.0625 g/cm^{3}}](https://tex.z-dn.net/?f=%5Cfrac%7B86.0%20g%7D%7B1.0625%20g%2Fcm%5E%7B3%7D%7D)
= 80.941 ![cm^{3}](https://tex.z-dn.net/?f=cm%5E%7B3%7D)
As, 80.941
of volume flows in 1 s
. Therefore, flow of volume in 1 hour will be calculated as follows.
In 1 hr = 80.941
= 291388.24 ![cm^{3}/hr](https://tex.z-dn.net/?f=cm%5E%7B3%7D%2Fhr)
Since, 1
= 0.001 L.
So, 291388.24 ![cm^{3}/hr \times 0.001 L/cm^{3}](https://tex.z-dn.net/?f=cm%5E%7B3%7D%2Fhr%20%5Ctimes%200.001%20L%2Fcm%5E%7B3%7D)
= 291.38824 L/hr
Thus, we can conclude that molar flow rate in mol/min is 54.89 mol/min and the volumetric flow rate in L/hr is 291.38824 L/hr.
Answer:
B-Sorry if this isn't right :/ Good luck.
Explanation:
Answer:
Lots of things here
Explanation:
Ammonia structure is written as NH3
carbon monoxide is CO
make bonds between O2, so there is 2 oxygen atoms per group,
anything with multiple elements bonded is a compound, thus your answer for carnon monoxide isnt correct, it should be CO for written and it is a compound. Fix your formula for ammonia and also max a bond between those two oxygens because it is O2 not O,
Your structure for SO2 is improper aswell, there are only 3 elements in this molecule, and usually the one out in front of the molecule is the central atom (except hydrogen). So it would go O-S-O for the structure, with only two bonding groups.
Cause their are both have difference s