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Svet_ta [14]
2 years ago
13

Helpppppppppppppppppppppppppppp

Chemistry
2 answers:
worty [1.4K]2 years ago
6 0

Answer:

evaporation or water runoff that's my tips

rain or thunder storm

Dvinal [7]2 years ago
3 0

Answer:

<h2><em><u>condensation</u></em><em><u> </u></em></h2>

Explanation:

Condensation is a process in which the evaporated liquid substance such as water vapor gets turned back to its liquid form water.

  • So, <em><u>condensation</u></em><em><u> </u></em> is the process in which water vapor changes to liquid .
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Hope this helps:):);)

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A competitive inhibitor of an enzyme-catalyzed reaction - cannot bind to the active site. - always interferes with product relea
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Answer:

is usually structurally similar to the substrate.

Explanation:

Competitive inhibitors resemble normal substrate and binds to enzyme at the active site usually and prevents substrate from binding.

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<u>Hence, correct option is - is usually structurally similar to the substrate.</u>

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Ethanol (C 2H 6O(l), ΔH o f = -277.69 kJ/mol) can be made by reaction of ethylene (C 2H 4(g) ΔH o f = 52.26 kJ/mol) with water (
lidiya [134]

Answer:

Enthalpy change = -44.12 kJ

Explanation:

<u>Given:  </u>

ΔH°f(C2H6O(l)) = -277.69 kj/mol  

ΔH°f(C2H4(g)) = 52.26 kj/mol  

ΔH°f(H2O) = -285.83 kj/mol  

<u>To determine:</u>

Enthalpy change for the formation of C2H6O

<u>Calculation:</u>

The given reaction is:

C2H4(g) + H2O(g)\rightarrow C2H5OH(g)

The enthalpy change for the reaction is given as;

\Delta H = \sum n(products)\Delta H^{0}f(products)-\sum n(reactants)\Delta H^{0}f(reactants)

where n(products) and n(reactants) are the moles of products and reactants

Substituting the appropriate values for n and ΔH°f:

\Delta H = 1\Delta H^{0}f(C2H6O)-[1\Delta H^{0}f(C2H4)+1\Delta H^{0}f(H2O)]

ΔH = -277.69-(52.26-285.83) = -44.12 KJ

4 0
3 years ago
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