The real distance between the two cities is 100000 feet.
<h3>How to use scales to estimate real life distances</h3>
Scales are applications of ratios in which maps are mostly based and that are used to estimate real distances between two points. Scales (r) are represented by the following formula:
r = m' / m (1)
Where:
- m - Real length
- m' - Reduced length
If we know that m' = 400 in and r = 4 in / 1000 ft, then the real distance between the two cities is:
m = m' / r
m = (400 in) / (4 in / 1000 ft)
m = 100000 ft
The real distance between the two cities is 100000 feet.
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Answer:
50
Step-by-step explanation:
The computation is shown below:
According to the question
(X ÷ 5) - 8 = 3
Now
X = (3 + 8) × 5
X = 55
Now in the case when it is decreased by 5
So, the value would be
= 55 - 5
= 50
The correct answer is PQ:OR is 1:3 , JK : KL is also 1:3. I know this because I took the test.
Answer:
The total change that will likely occur in 2 years is mg/L
Step-by-step explanation:
Given : The first year, they found the chloride concentration changed by mg/L .
It is estimated that the chloride concentration will change mg/L the next year.
To find : What is the total change that will likely occur in 2 years?
Solution :
The chloride concentration changed by mg/L in first year.
The chloride concentration will change mg/L the next year.
The total change that will likely occur in 2 years is
In a mixed fraction - mg/L
First we do what’s in the parentheses.
7 • 10 - 5 = 70 - 5 = 65
Then we do exponents. We don’t have any so we skip this step.
Then we do multiplication and division.
65 • 0.0007 = 0.0455
We don’t have any addition or subtraction so we skip this step.
The solution is 0.0455.