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maksim [4K]
2 years ago
8

Pls help I’ll brainlest I’m failing

Mathematics
2 answers:
saveliy_v [14]2 years ago
7 0

Step-by-step explanation:

why ? you have started it correctly already, as I can see by the margins you made on the graph.

you analyzed the problem correctly, approached the solution correctly and gathered all necessary data.

so, I am not sure, what your problem is.

if you don't know what a slope is, then I don't understand why you did what you did so far.

the slope is expressed as the ratio

y coordinate change / x coordinate change

when going from one point to the other.

for these 2 points you marked, you also showed that

x changes by +2 (from 2 to 4).

y changes by +6 (from -4 to 2).

so, the slope is +6/+2 = 3.

that's it. that is all to it.

Sergeu [11.5K]2 years ago
3 0
It’s actually the closet points or box it’s 3/1 or you can put three
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Describe the continuity of the graphed function
marusya05 [52]

we know that

Any function f(x) is continuous at x=a only if

\lim_{x \to a-} f(x) = \lim_{x \to a+} f(x)=f(a)

We can see that this curve is smooth everywhere except at x=3

so, we will check continuity at x=3

Left limit is:

\lim_{x \to 3-} f(x) = -\infty

Right limit is:

\lim_{x \to 3+} f(x) = +\infty

Functional value:

f(3)= DNE

we can see that left limit is not equal to right limit

so, limit does not not exist

so, this function is discontinuous at x=3

Since, limit does not  exist  

so, there will be non-removal discontinuity at x=3

so, option-C........Answer


5 0
3 years ago
Simplify each expression. 16 1/4. 49 1/2. 10001/3-64 1/6
Crazy boy [7]
The answer for the first one is 4 the sacend one is 49/2 the thirst one is 33223
7 0
3 years ago
Phil has 5 times as many toy race cars as Richard has. Phil has 425 toy race cars. How many race cars does Richard have? *
Wewaii [24]

Answer:

85

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
Someone help me out please
uysha [10]

1 step (B): raise both sides of the equation to the power of 2.

(\sqrt{x+3}-\sqrt{2x-1})^2=(-2)^2,\\   (x+3)-2\sqrt{x+3}\cdot \sqrt{2x-1}+(2x-1)=4,\\ 3x+2-2\sqrt{x+3}\cdot \sqrt{2x-1}=4.

2 step (A): simplify to obtain the final radical term on one side of the equation.

-2\sqrt{x+3}\cdot \sqrt{2x-1}=4-3x-2,\\ -2\sqrt{x+3}\cdot \sqrt{2x-1}=2-3x,\\ 2\sqrt{x+3}\cdot \sqrt{2x-1}=3x-2.

3 step (F): raise both sides of the equation to the power of 2 again.

(2\sqrt{x+3}\cdot \sqrt{2x-1})^2=(3x-2)^2,\\ 4(x+3)(2x-1)=(3x-2)^2.

4 step (E): simplify to get a quadratic equation.

4(2x^2-x+6x-3)=(3x)^2-2\cdot 3x\cdot 2+2^2,\\ 8x^2+20x-12=9x^2-12x+4,\\ x^2-32x+16=0.

5 step (D): use the quadratic formula to find the values of x.

D=(-32)^2-4\cdot 16=1024-64=960, \\ \sqrt{D} =8\sqrt{5} ,\\ x_{1,2}=\dfrac{32\pm 8\sqrt{5}}{2} =16\pm 4\sqrt{5}.

6 step (C): apply the zero product rule.

x^2-32x+16=(x-16-4\sqrt{5}) (x-16+4\sqrt{5}) ,\\ (x-16-4\sqrt{5}) (x-16+4\sqrt{5}) =0,\\ x_1=16+4\sqrt{5} ,x_2=16-4\sqrt{5}.

Additional 7 step: check these solutions, substituting into the initial equation.

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oe hello im from nepal follow me plz bro

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