Simplify the following expression: 2x − 6y + 3x2 + 7y − 14x. 3x2 + 12x + y 3x2 − 12x − y 3x2 − 12x + y 3x2 − 12x − 13y

2 answers:

8 0

-6x-13y
2x+(3x2)-14x+(3x2)+12x+(3x2)-12x+(3x2)-12x+(3x2)-12x
2x+6x-14x+6x+12x+6x-12x+6x-12x+6x-12x=-6
-6y+7y+1y-1y+1y-13y=-13y
if a letter is by itself then there is automatically a one in front of it

ra1l [238]4 years ago

8 0

3x2 − 12x + y would be your answer

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An example of consecutive odd integers is 23, 25, 27, and 29. Find four consecutive odd integers with a sum of 160. Show your wo

Andrew [12]

Step1: Define an odd integer.
Define the first odd integer as (2n + 1), for n = 0,1,2, ...,
Note that n is an integer that takes values 0,1,2, and so no.

Step 2: Create four consecutive odd integers.
Multiplying n by 2 guarantees that 2n will be zero or an even number.
Therefore (2n + 1) is guaranteed to be an odd number.
By adding 2 to the odd integer (2n+1), the next number (2n+3) will also be an odd integer.

Let the four consecutive odd integers be
2n+1, 2n +3, 2n +5, 2n +7

Step 3: require that the four consecutive integers sum to 160.
Because the sum of the four consecutive odd integers is 160, therefore
2n+1 + 2n+3 + 2n+5 + 2n +7 = 160
8n + 16 = 160
8n = 144
n = 18

Because 2n = 36, the four consecutive odd integers are 37, 39, 41, 43.

Answer: 37,39,41,43

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3 years ago

Halloween Candy Halloween is Kelly's favorite holiday of the year! Based on experience, Kelly knows that on average, each house

LuckyWell [14K]

Using the normal distribution and the central limit theorem, it is found that there is an approximately 0% probability that the total number of candies Kelly will receive this year is smaller than last year.

Normal Probability Distribution

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
By the Central Limit Theorem, for n instances of a normal variable, the mean is $n\mu$ while the standard deviation is $s = \sigma\sqrt{n}$ .

In this problem:

Mean of 4 candies, hence $\mu = 4$ .
Standard deviation of 1.5 candies, hence $\sigma = 1.5$ .
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