Question

The perpendicular bisector of the line segment joining the points A (-8, 0) and B (8, 0) passes through a point (0,k). the value of k is

Answer 1

The steepness of a line is determined by its slope. The value of "k" is 0

First, we need to find the slope of the line passing through the points A (-8, 0) and B (8, 0) as shown:

$m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{0-0}{8-(-8)}\\m=\frac{0}{16}\\m =0$

To get the value of k, we will equate the slope of the perpendicular line which is 0 to the slope of the line passing through A (-8, 0)  and (0, k)

$m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{k-0}{0-8}\\m=\frac{k}{-8}\\0=\frac{k}{-8}\\k = 0$

Hence the value of "k" is 0

Learn more on  slope here: brainly.com/question/16949303