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xz_007 [3.2K]
2 years ago
8

Which option is a false statement about Christopher Columbus?

Mathematics
1 answer:
Lisa [10]2 years ago
7 0
4th one is defo right so it’s one of the rest
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Juan is drawing the two-dimensional net of a rectangular solid, but he made a mistake. What error did Juan make, and how can he
dsp73

Answer:

D.The prism is missing a sixth face, which should be colored white.

Step-by-step explanation:

The shape does not have 2 bases in the picture showed. Therefore, it needs another white square.

Hope it helps! have a good day! :)))))

7 0
3 years ago
Read 2 more answers
Find the solutions of the quadratic equation - 2^2+ 3x – 3 = 0
Assoli18 [71]

Answer:

-1/3

Step-by-step explanation:

2^2 + 3x - 3 = 0

4 - 3 + 3x = 0

1 + 3x = 0

x = -1/3

Hope it helps

7 0
2 years ago
Suppose the graph of a cubic polynomial function has the same zeroes and passes through the coordinate (0, -5). Write the equati
amid [387]
In this we know all three zeros and one point from which the graph pass.
So we will let specific cubic polynomial function of the form
f(x) = a(x - x_1)(x-x_2)(x-x_3)

As we know zeros are that point where we will get value of function equal to zero. So it is basically in form (x_n , 0)

SO in given question zeros are (2 , 0) , (3, 0) and (5,0)
So we can say x_1 = 2 , x_2 = 3 , x_3 = 5

So required equation is
f(x) = a (x-2)(x-3)(x-5)
              = a[(x^2 - 2x - 3x + 6)(x-5)]
              = a[(x^2 - 5x+6)(x-5)]
              = a(x^3 - 5x^2 + 6x- 5x^2 + 25x - 30)
              = a(x^3 - 10x^2+31x-30)
Now we have one point (0 , -5) from which graph passes.
So we say at x = 0 , f(x) = -5
-5= a (0-0+0 - 30)
-5 = -30a
a =  \frac{-5}{-30} =  \frac{1}{6}
So required equation of cubic polynomial is
f(x) =  \frac{1}{6}(x^3 -10x^2+31x-30)

For finding y - intercept we simply plugin x = 0 in given equation.
As we know at x = 0 , value of function is -5.
So y - intercept is -5.
4 0
3 years ago
Read 2 more answers
Write a quadratic function in standard form with a leading coefficient of 1 for the given set of zeros. 7 and 4
Viefleur [7K]

We are given : Zeros x=7 and x=4 and leading coefficent 1.

In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.

For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).

So, we need to multiply (x-7) and (x-4) by foil method.

We get

(x-7)(x-4) = x*x + x* -4 -7*x -7*-4

x^2 -4x -7x +28.

Combining like terms, we get

-4x-7x = -11x

x^2 -4x -7x +28 = x^2 -11x +28.

Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.

We get

1(x^2 -11x +28) = x^2 -11x +28.

Therefore, the required quadratic function in standard form is x^2 -11x +28.


6 0
3 years ago
Help please, look at picture for question
alexgriva [62]

Answer:

whats the title of the page ill find the answers to thw whole sheet n and while your  at it do you know Why was Kor surprised that Groening embraced her???

Step-by-step explanation:

8 0
3 years ago
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