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Murrr4er [49]
2 years ago
6

Make m the subject of the formula L = m + n

Mathematics
1 answer:
Elza [17]2 years ago
7 0
The ANSWER is m = n - L
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Help ASPP<br><br>-3/5 x = 18 <br>-30<br>-10 4/5<br>10 4/5<br>30​
kompoz [17]

Answer:

-30

Step-by-step explanation:

move and divide -3/5 to the right side

-3/5x = 18

x=18÷(-3/5)

x= -30

5 0
3 years ago
What is the answer to this
son4ous [18]
I thin the answer is D.DF

6 0
3 years ago
A cylinder is sliced horizontally, parallel to its base, and vertically. Which of the following could represent cross sections o
Misha Larkins [42]

C- CIRCLE AND RECTANGLE!

(~ ̄³ ̄)~( ˘ ³˘)♥

5 0
3 years ago
Read 2 more answers
Dos cuadrados de lado
Kaylis [27]

La franja amarilla del rectángulo tiene un área de 30 centímetros cuadrados.

<h3>¿Cuál es el área de la franja amarilla del rectángulo?</h3>

En este problema tenemos un rectángulo formado por dos cuadrados que se traslapan uno al otro. La franja amarilla es el área en la que los cuadrados se traslapan. La anchura del rectángulo es descrita por la siguiente ecuación:

(10 - x) + 2 · x = 17

Donde x se mide en centímetros.

A continuación, despejamos x en la ecuación descrita:

10 + x = 17

x = 7

Ahora, el área de la franja amarilla se determina mediante la fórmula de area de un rectángulo:

A = b · h

Donde:

  • b - Base del rectángulo, en centímetros.
  • h - Altura del rectángulo, en centímetros.
  • A - Área del rectángulo, en centímetros cuadrados.

A = (10 - 7) · 10

A = 3 · 10

A = 30

El área de la franja amarilla del rectángulo es igual a 30 centímetros cuadrados.

Para aprender más sobre áreas de rectángulos: brainly.com/question/23058403

#SPJ1

8 0
1 year ago
B2≤4<br><br> What is the solution to the inequality?<br><br> b≥8<br><br> b≤8<br> b≤2<br> b≥2
Allisa [31]
The solution is the third one:
b≤2
8 0
4 years ago
Read 2 more answers
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