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stira [4]
3 years ago
14

- 7th Grade Work - Please help with these two ; - ;

Mathematics
2 answers:
Andrew [12]3 years ago
8 0

Answer:

answer for the first one

Step-by-step explanation:

i belive that the cost before is $538.51

liq [111]3 years ago
7 0

Answer:

My mind is dead

Step-by-step explanation:

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What is the unit cost per bottle if a pack of 4 bottles of juice sells for$3
Zina [86]

Answer:

$1.33 Per Bottle

Step-by-step explanation:

Simply divide 4 by 3 to get 1.33

1.33 is the cost

you can verify this by multiplying 1.33 x 3 to get 4

5 0
3 years ago
What is the limit of f(x) = 5 as x approaches ? (if an answer does not exist, enter dne.)
lions [1.4K]

The value of lim f(x) + g(x) in the information given is 2

<h3>How to calculate the value?</h3>

From the given information, the limit of f(x) is given as 5/4 and Lim g(x) = 3/4.

Therefore, lim f(x) + g(x)

= 5/4 + 3/4

= 8/4

= 2

Learn more about limit on:

brainly.com/question/12383223

#SPJ4

Complete question

What is the limit of f(x) = 5/4 + g(x) = 3/4 as x approaches c?

3 0
2 years ago
Which change will quadruple the lateral surface area of a cone?
vlada-n [284]
Don't know try something else it will probably help
6 0
3 years ago
Read 2 more answers
Sally is shopping for diapers and sees a box with 216 diapers for \$39.98 and a box with 88 diapers for \$24.99 . Which option h
Mekhanik [1.2K]
The first step is to find out the value of one diaper for each equation

39.98/216 = 0.18
Therefore one diaper is for 0.18 cents

24.99/88 = 0.28
Therefore one diaper is for 0.28 cents

At the end the first deal is better
7 0
3 years ago
Read 2 more answers
How much more would $1000 earn in 5 years in an account compounded continuously than an account compounded quarterly if the inte
choli [55]
\bf ~~~~~~ \textit{Compounding Continuously Interest Earned Amount}\\\\&#10;A=Pe^{rt}\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\to& \$1000\\&#10;r=rate\to 3.7\%\to \frac{3.7}{100}\to &0.037\\&#10;t=years\to &5&#10;\end{cases}&#10;\\\\\\&#10;A=1000e^{0.037\cdot 5}\implies A=1000e^{0.185}\\\\&#10;-------------------------------\\\\

\bf ~~~~~~ \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\to &\$1000\\&#10;r=rate\to 3.7\%\to \frac{3.7}{100}\to &0.037\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{quarterly, thus four}&#10;\end{array}\to &4\\&#10;t=years\to &5&#10;\end{cases}&#10;\\\\\\&#10;A=1000\left(1+\frac{0.037}{4}\right)^{4\cdot 5}\implies A=1000(1.00925)^{20}

compare both amounts.
8 0
3 years ago
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