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3 years ago

6 - 1/3x = -1 what does x equal please explain the process

Mathematics

2 answers:

NISA [10]3 years ago

5 0

X = -21

Step 1: Subtract 6 from both sides -1/3x = -7
Step 2: Divide -1/3 from both sides x = -21

hodyreva [135]3 years ago

4 0

Answer: x = -21

Step-by-step explanation:

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Mia has $40 in a savings account. She will start adding $5 to her account each week. Juan has $15 in a savings account. He will

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Y=40+5x
For an example, say Mia wanted to add $5 into her account each week for 2 weeks.
y=40+5(2)
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3 years ago

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Anwser:

y = 2x

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3 years ago

The slope of a line is 2. The y-intercept of the line is –6. Which statements accurately describe how to graph the function?

garik1379 [7]

Answer:

Step-by-step explanation:

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3 years ago

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A rectangle has a perimeter of 18 cm.its length is 5 cm greater than its width.find the dimensions.

Marat540 [252]

P=18
l=5 cm greater than the width
w=5 less than the length

USE YOUR NUMBER SENSE!!! - just plug in different number below 4 to figure out the width

3=w 3+5=8 8+8=16+6=22 WILL NOT WORK

2=w 2+5=7 7+7=14 14+2+2= 18 WE HAVE A WINNER!!!!

FInal Answer: width: 2 cm and length: 7 cm

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3 years ago

The students in Mr. Wilson's Physics class are making golf ball catapults. The

Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is $0 \leq x \leq 48.6\ ft$ and the range is $0 \leq y \leq 8.3\ ft$

Step-by-step explanation:

we have

$y=-0.014x^{2} +0.68x$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's distance from the catapult in feet

y is the flight of the balls in feet

Part a) How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-0.014x^{2} +0.68x=0$

$a=-0.014\\b=0.68\\c=0$

substitute in the formula

$x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}$

$x=\frac{-0.68(+/-)0.68} {(-0.028)}$

$x=\frac{-0.68(+)0.68} {(-0.028)}=0$

$x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft$

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

$y=-0.014x^{2} +0.68x$

Find out the derivative and equate to zero

$0=-0.028x +0.68$

Solve for x

$0.028x=0.68$

$x=24.3$

<em>Alternative method</em>

To determine the x-coordinate of the vertex, find out the midpoint between the x-intercepts

$x=(0+48.6)/2=24.3\ ft$

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

$y=-0.014(24.3)^{2} +0.68(24.3)$

$y=8.3\ ft$

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A reasonable domain is the distance between the two x-intercepts

$0 \leq x \leq 48.6\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

we have the interval -----> [0,8.3]

$0 \leq y \leq 8.3\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

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3 years ago