Answer:
-3/5-13i/10
Step-by-step explanation:
Answer:
Step-by-step explanation:
If we take out the extra $3, we can group the bills into one each of $5 and $1, for a value of $6. There will be 7 such groups in the remaining $42.
That means there are 7 bills of the $5 denomination, and 3 more than that (10 bills) of the $1 denomination.
There are 7 $5 bills and 10 $1 bills.
_____
If you want to write an equation, it is usually best to let a variable stand for the most-valuable contributor. Here, we can let x represent then number of $5 bills. Then the value of the cash box is ...
5x +(x+3) = 45
6x = 42 . . . . . . . . subtract 3, collect terms
x = 7 . . . . . . . . . . . there are 7 $5 bills
x+3 = 10 . . . . . . . . there are 10 $1 bills
You may notice that this working parallels the verbal description above. (After we subtract $3, x is the number of $6 groups.)
Answer:
c 1.175 L
Step-by-step explanation:
you just add the two amounts of soap he put into the container and subtract it from the total amount of soap he had, 2 L.
Answer:
Step-by-step explanation:
g(x) = 3x + 5
g(3) = 3(3) + 5
g(3) = 9 + 5
g(3) = 14
-----------------------
f(x) = 2x² + 3
f(g(3)) = 2(g(3)) + 3
f(14) = 2(14²) + 3
f(14) = 2(196) + 3
f(14) = 392 + 3
f(14) = 395
-----------------------------
f(g(3)) = 395
Answer:
C 36
Step-by-step explanation:
When we have to exponents to the same base, and we are dividing them, we can subtract the exponents
a^b ÷ a^c = a^ (b-c)
6^7 ÷ 6^5 = 6^(7-5)
= 6^(2)
= 36
