5x + 2 y = 7<br> 4x + y = 8

Multiply. Check picture.

VashaNatasha [74]

The answer is $3x^4-13x^3-x^2-11x+6$ .

Solution:

Use algebraic identity: $a^m\times a^n=a^{m+n}$

For example: $x^2\times x=x^{2+1}=x^3$

Given expression $(x^2-5x+2)$ and $(3x^2+2x+3)$ .

To multiply these equations.

$(x^2-5x+2)\times(3x^2+2x+3)$

$=x^2(3x^2+2x+3)-5x(3x^2+2x+3)+2(3x^2+2x+3)$

$=(3x^4+2x^3+3x^2)+(-15x^3-10x^2-15x)+(6x^2+4x+6)$

$=3x^4+2x^3+3x^2-15x^3-10x^2-15x+6x^2+4x+6$

Combine like terms together.

$=3x^4+(2x^3-15x^3)+(3x^2-10x^2+6x^2)-15x+4x+6$

$=3x^4-13x^3-x^2-11x+6$

$(x^2-5x+2)\times(3x^2+2x+3)=3x^4-13x^3-x^2-11x+6$

Hence the answer is $3x^4-13x^3-x^2-11x+6$ .

3 0

3 years ago

Plzzzz answer question 14

viktelen [127]

Its D because when you use some graph paper point A and point B are 6 units away from each other

6 0

3 years ago

Find the area of the shape below.

m_a_m_a [10]

Answer:

$A_{shape}=A_{triangle}+A_{square}\\\\A_{shape}=(\frac{bh}{2}+s^2)\ units^2$

Step-by-step explanation:

I assume that it is a composed figure formed by a triangle and a square.Since you did not give the dimensions of the triangle and the dimensions of the square, I will giveyou a general explanation about how to solve this exercise.

The area of the shape will be the sum of the the area of the square and the area of the triangle.

Then, you need to remember that the area of a triangle can be calculated with the following formula:

$A_{triangle}=\frac{bh}{2}$

Where "b" is the base and "h" is the height.

And the area of a square can be found with this formula:

$A_{square}=s^2$

Where "s" is the length of any side of the square.

Therefore, the area of the shape will be

$A_{shape}=A_{triangle}+A_{square}\\\\A_{shape}=(\frac{bh}{2}+s^2)\ units^2$

3 0

3 years ago

Solve the inequality algebraically<br><br><br>2x^2 -12 <= -5x

Mazyrski [523]

Hello!

To solve this question, find the roots and create test intervals.
Evaluation: -4<x<3/2

Have a wonderful day! :)

-L

8 0

3 years ago

Coach Jamison wants to celebrate the final win of the school's baseball season with a trip to the local fast food place. The tea

PIT_PIT [208]

So we have 2 variables here: tacos and orders of nachos.

When we translate the paragraphs into equation: $28t + 27n = 114.80 \\ \\ 12t + 3n = 37.20$

Now, in this situation we can make use the elimination method by converting 3n to -27n.

$- 108t - 27n = - 334.8$

Add both equations: $28t + 27n - 108t - 27n = 114.8 - 334.8 \\ \\ - 80t = - 220 \\ \\ t = 2.75$

So we find that one taco costs $2.75.

We can plug this into any of the first two equations to find n: $12 \times 2.75 + 3n = 37.2 \\ \\ 33 + 3n = 37.2 \\ \\ 3n = 4.2 \\ \\ n = 1.4$

So one order of nachos cost $1.40.

4 0

3 years ago

5x + 2 y = 7 4x + y = 8