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1 year ago

Write five and ninety-five hundredths as a decimal number.

Mathematics

2 answers:

kiruha [24]1 year ago

4 0

Answer: 5.95

Step-by-step explanation: I know that 5 and ninety five hundredths is written like this: 5 95/100. I turned it into a decimal by making it into a improper fraction, 595/100 then divididing the numerator by the denominator. The answer would be 5.95.

poizon [28]1 year ago

3 0

Answer:

5.95

Step-by-step explanation:

Five and ninety-five hundredths as a decimal number is 5.95.

Hoped this helped.

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5. Maria is tracking the number of miles she runs in one week. She is using the track at her

777dan777 [17]

Answer:

0.00310 miles

Step-by-step explanation:

Maria runs 5 m each week. We need to find how miles she run. It means we need to convert meters to miles. The relation between meter and yards is as follows :

1 meter = 1.09361 yards

Also, 1 mile = 1760 yards

It means,

1 mile = 1609.34 m

1 m = (1/1609.34) miles

$5\ m=\dfrac{5}{1609.34}\ \text{miles}\\\\=0.00310\ \text{miles}$

So, she will cover 0.00310 miles.

6 0

2 years ago

Josie is training for a race. The ratio of

anzhelika [568]

The number of minutes that Josie will take is 80 minutes.

<u>Explanation:</u>

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Explanation:

Ratio of the number of minutes to the number of miles = $\frac{24}{3}$

Number of miles = 10

Number of minutes = ?

Let x be the number of minutes

According to the question,

$\frac{24}{3} = \frac{x}{10} \\\\x = \frac{240}{3} \\\\x = 80$

Therefore, the number of minutes that Josie will take is 80 minutes.

6 0

2 years ago

The USA Today reports that the average expenditure on Valentine's Day is $100.89. Do male and female consumers differ in the amo

Aloiza [94]

Answer:

$a)\ \ \bar x_m-\bar x_f=67.03\\\\b)\ \ E=15.7416\\\\c)\ \ CI=[51.2884, \ 82.7716]$

Step-by-step explanation:

a. -Given that:

$n_m=41\ , \ \sigma_m=33, \bar x_m=135.67\\\\n_f=37. \ \ ,\sigma_f=20, \ \ \bar x_f=68.64$

#The point estimator of the difference between the population mean expenditure for males and the population mean expenditure for females is calculated as:

$\bar x_m-\bar x_f\\\\\therefore \bigtriangleup\bar x=135.67-68.64\\\\=67.03$

Hence, the pointer is estimator 67.03

b. The standard error of the point estimator, $\bar x_m-\bar x_f$ is calculated by the following following:

$\sigma_{\bar x_m-\bar x_f}=\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}$

-And the margin of error, E at a 99% confidence can be calculated as:

$E=z_{\alpha/2}\times \sigma_{\bar x_m-\bar x_f}\\\\\\=z_{0.005}\times\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}\\\\\\=2.575\times \sqrt{\frac{33^2}{41}+\frac{20^2}{37}}\\\\\\=15.7416$

Hence, the margin of error is 15.7416

c. The estimator confidence interval is calculated using the following formula:

$\bar x_m-\bar x_f\ \pm z_{\alpha/2}\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}$

#We substitute to solve for the confidence interval using the standard deviation and sample size values in a above:

$CI=\bar x_m-\bar x_f\ \pm z_{\alpha/2}\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}\\\\=(135.67-68.64)\pm 15.7416\\\\=67.03\pm 15.7416\\\\=[51.2884, \ 82.7716]$