The first one is 20 and the second one is 19 and the third one is 25 and the fourth one is 15 and the fifth one is 11 and the sixth one is 28
One method is to round 997 up to 1000, multiply by 8, and then subtract 8 times 3. This would give you the solution of 7976.
Another method (Which I personally wouldn't use) is to recursively double 997. This is more difficult, although effective. After you double 997, double the resulting number, and then double the resulting number from that, you have the solution. This is because 2^3 is 8.
Option D:
15c ≤ 200
Solution:
Let c be the number of cases of tea bags.
Cost of each tea bag = 15 gold coins
Total gold coins Mad have = 200
<u>Set up an inequality:</u>
Cost of c tea bags = 15 × c = 15c
Mad can buy tea bags at most 200 gold coins.
(At most 200 means 200 is the greater value)
15 × c ≤ 200
15c ≤ 200
Hence option D is the correct answer.
Answer:
a i think
Step-by-step explanation:
It would be the last choice Joelle: 155, Anita: 270
