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tankabanditka [31]
3 years ago
14

15 POINTS Find x if P=(3x+5) and Q=(8x-12)

Mathematics
1 answer:
wlad13 [49]3 years ago
7 0

the answer for this question is p=5/3 ,(q)=3/2

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PLEASE ANSWER + BRAINLIEST!!
Firdavs [7]
The correct answer is B. (-1, 3) 



Hope this helps :)
6 0
3 years ago
I need help on this. The portrait studio can buy photographs on canvas. The small canvas photograph print is $20 and the large c
Whitepunk [10]
<h3>Answer:</h3>
  • 6 large prints
  • 12 small prints
<h3>Step-by-step explanation:</h3>

<em>Numerical Reasoning</em>

Consider a set of prints that consists of 2 small prints and one large print (that is, twice as many small prints as large). The value of that set will be ...

... 2×$20 +45 = $85

To have revenue of at least $510, the studio must sell ...

... $510/$85 = 6

sets of prints. That is, the studio needs to sell at least 6 large prints and 12 small ones.

_____

<em>With an equation</em>

Let x represent the number of large prints the studio needs to sell. Then 2x will represent the number of small prints. Total sales will be ...

... 20·2x +45·x ≥ 510

... 85x ≥ 510

... x ≥ 510/85

... x ≥ 6

The studio needs to sell at least 6 large prints and 12 small prints.

8 0
3 years ago
If cos θ = .62 and if 0&lt;θ&lt;90 what is the approximate value of sin θ to the nearest hundredth
Deffense [45]
\cos\Theta=0.62\\\\\text{Use:}\ \sin^2\alpha+\cos^2\alpha=1\\\\\sin^2\Theta+(0.62)^2=1\\\\\sin^2\Theta+0.3844=1\ \ \ |-0.3844\\\\\sin^2\Theta=0.6156\to\sin\Theta=\pm\sqrt{0.6156}\\\\\sin\Theta_1\approx-0.78\ \vee\ \sin\Theta\approx0.78\\\\\Theta\in(0^o;\ 90^o),\ therefore\ \sin\Theta \ \textgreater \  0\to\boxed{\sin\Theta\approx0.78}
5 0
3 years ago
It costs $50 to join a bowling club plus a monthly fee, the total costs for the year is $350
kvasek [131]
$25 a month :)  (its too short so i hope you have a lovely day)
5 0
3 years ago
Find the area of the shaded region. Round your answer to the nearest tenth.
Troyanec [42]

Area of the square = (9 m)^2 = 81 m^2

The four circular sectors combine to form a circle with diameter 9 m, hence radius 4.5 m.

Area of the circle = π (4.5 m)^2 = 20.25π m^2

Then the area of the shaded region is

81 m^2 - 20.25π m^2 ≈ 17.4 m^2

7 0
3 years ago
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