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Maslowich
3 years ago
10

What to the fourth power equals 0.0625?

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
6 0
0.5 to the fourth power equals 0.0625.
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Will Mark The Brainiest that is extra points aka FULL POINTS
valentina_108 [34]
Hello!

We can solve this by using substitution

we can plug y = x - 1 into the other equation

So 2x - 3( x - 1) = -1

We can distribute the -3 to (x - 1)

2x - 3x + 3 = -1

Combine like terms

-x + 3 = -1

Subtract 3 from both sides

-x = -4

Since x is negative we can multiply both sides by -1

x = 4

We can plug x into the first equation

y = (4) - 1

y = 3

The answers are x = 4 and y = 3

Hope this helps!
6 0
3 years ago
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What is its equation <br> slope-intercept form ?
aivan3 [116]
Y=1/8x
hope this helped!
5 0
3 years ago
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0.25% of 42 is what number
Alborosie

Answer:

0.105

Step-by-step explanation:

0.25/100 x 42 = 0.105

6 0
3 years ago
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A movie store purchases boxes of gumballs. Each box has 500 gumballs in it and costs $10.00. How much will the store have to sel
iren2701 [21]
I got 750 gum balls.
Each gum ball cost 0.2 cents. 0.2x100=10.00. If you wanted $15 then you would do 15.00 divided by 2 which would give you 750
7 0
4 years ago
In the diagram below, AB I AC, CD= CE and m B = 48º.Find m DEB.
Jet001 [13]

In the given triangle the sum of the interior angles of triangle ACB is equal to 180 degrees, therefore, we have the following relationship:

\angle CAB+\angle ABC+\angle BCA=180

Replacing the values we get:

90+48+\angle BCA=180

Solving the operations:

138+\angle BCA=180

Now we solve for angle BCA by substracting 138 to both sides:

\begin{gathered} \angle BCA=180-138 \\ \angle BCA=42 \end{gathered}

Now, since segments CD and CE are equal, this means that triangle CDE is an isosceles triangle, therefore, its base angles are the same, and we have the following relationship:

\angle CDE+\angle DEC+\angle ECD=180

Replacing the known values:

2\angle DEC+42=180

Now we solve for angle DEC by subtracting 42 to both sides:

\begin{gathered} 2\angle DEC=180-42 \\ 2\angle DEC=138 \end{gathered}

Now we divide both sides by 2:

\begin{gathered} \angle DEC=\frac{138}{2} \\ \angle DEC=69 \end{gathered}

Now, angles DEC and DEB are supplementary, therefore, their sum adds up to 180, therefore, we have:

\angle DEC+\angle\text{DEB}=180

Replacing the known angle:

69+\angle DEB=180

Subtracting 69 to both sides:

\begin{gathered} \angle DEB=180-69\rbrack \\ \angle DEB=111 \end{gathered}

Therefore, angle DEB measures 111 degrees.

3 0
1 year ago
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