Slope is 5/4 and y-intercept is -4
hope this helps
The point-slope form of the equation for a line can be written as
... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)
Your function gives
... f'(h) = m
... f(h) = k
a) The tangent line is then
... y = 5(x -2) +3
b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.
... y = (-1/5)(x -2) +3
_____
You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.
In standard form, the tangent line's equation is 5x -y = 7. The normal line's equation is x +5y = 17.
Answer:
option B
Step-by-step explanation:
Sum of interior angles of a polygon with n sides:
![[ \ because \ straight \ line \ angle = 180^\circ \ ]](https://tex.z-dn.net/?f=%5B%20%5C%20because%20%5C%20straight%20%5C%20line%20%5C%20angle%20%3D%20180%5E%5Ccirc%20%5C%20%5D)
That is ,
OR
Sum of exterior angles of a regular polygon = 360
Given 1 exterior angle of the regular polygon is 40
Therefore ,
Answer: Multipy and ADD then eqaul the vaual
Step-by-step explanation:
Y = 2x³, when x = -3
<span>y = 2*(-3)³
</span>
<span>y = 2*-27
</span>
y = -54
